An atom is defined as having the same number of electrons (negative charge), protons (positive charge) and neutrons (no charge). This means that it will have the same amount of negative and positive charge, giving it a net zero charge. On the other hand, an ion has different amount of electrons and protons.
Answer:
Se necesita la información de las siguientes variables:
(i) Fuerza normal entre los pies y la superficie.
(ii) Masa del atleta de halterofilia.
(iii) Masa de la barra de pesas.
(iv) Aceleración gravitacional.
(v) Fuerza normal entre la barra de pesas y la superficie.
(vi) Aceleración neta del centro de gravedad del sistema.
Explanation:
Sea el conjunto del atleta de halterofilia y la barra de pesas el sistema físico a estudiar. El fenómeno de levantamiento puede modelarse como traslación pura. Por las leyes de Newton tenemos que se necesita las siguientes variables para determinar la magnitud de la fuerza para levantarla (fuerza normal entre la mano y la barra de pesas) se requiere las siguientes variables:
(i) Fuerza normal entre los pies y la superficie.
(ii) Masa del atleta de halterofilia.
(iii) Masa de la barra de pesas.
(iv) Aceleración gravitacional.
(v) Fuerza normal entre la barra de pesas y la superficie.
(vi) Aceleración neta del centro de gravedad del sistema.
Answer:
I would say pushing it from the top because when you push anything from the top it basically flips over. You can go ahead and try to push anything forward from the top and starts tipping forward. I think the reason would be because you're putting weight only on the top of the tv and that is what would cause it to topple
Explanation: Hope this helps:)
Answer:
Option E is correct, 79 μC
Explanation:
Given that,
A capacitor of capacitance C1
C1 = 3 μF
The capacitor is charge to 40V
V1=40V
Another capacitor of capacitance
C2 = 5 μF
Charge to 18V,
V2 =18V
When the positive terminal of one is connected to the negative terminal of the other, then, this is a series connection.
The capacitor are connected in series.
Series connection have the same charge.
Equivalent capacitance for series connection is give as
Ceq = C1 + C2
Ceq = 3μF + 5μF
Ceq = 8μF
Charge in a capacitor is given as
q = CV
Then, charge on Capacitor 1.
q1 = C1V1
q1 = 3μF × 40V
q1 = 120μC
Charge on capacitor 2
q2 = C2V2
q2 = 5μF × 18V
q2 = 90μC
The total charge in the circuit is
Qeq =q1 + q2
Qeq =90 + 120
Qeq = 210 μC
Then, the combine voltage in the circuit is
Qeq = CeqV
Then, V= Qeq/Ceq
V= 210 μC / 8 μC
V=26.25Volts
Then the charge on the 3μF is
q =CV
q =3 μC × 26.25 V
q = 78.75 μC
q ≈ 79 μC
Final answer is E.