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vladimir2022 [97]
2 years ago
6

How much work can a 22kw car engine do in 60 seconds

Physics
2 answers:
const2013 [10]2 years ago
8 0

Answer:

Work done = 1320000J or 1.32 × 10^6J

Explanation:

power =22kw = 22000w

Time = 60seconds

From: power = work done/ Time

work done = power × time

work done = 22000 × 60

work done = 1320000J or 1.32 ×10^6 J

Sindrei [870]2 years ago
6 0

Answer:

13.2 x 10^5 J

Explanation:

Power = work/time

Given

Power = 22kw

= 22 x 1000 = 22000w

Time = 60 secs

Therefore

22000 = work/60

Cross multiply

Work = 22000 x 60

= 1320000

= 13.2 x 10^5J

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Jennifer runs 5 miles east, then stops to take a break. after her break, she continues running 4 more miles east. what is her di
andreev551 [17]

Jennifer runs 5 miles east, then stops to take a break. after her break, she continues running 4 more miles east.

In this the total distance she covers is 9 miles and the total displacement is also the same as the distance that is 9 miles.

<h3>What is the difference between distance and displacement?</h3>

Displacement is the shortest distance between initial and final position, or we can say it is the straight-line distance between initial and final position.

Whereas distance is considered as the total path length covered from initial position till the final position. The Displacement of a body is always less than or equal to the distance.

Displacement can be zero in case the initial and final positions coincide, but distance can never be zero.

To know more about distance and displacement, visit:

brainly.com/question/3243551

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7 0
2 years ago
When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal speed. Once he has reache
Masteriza [31]

Answer:

b) True.    the force of air drag on him is equal to his weight.

Explanation:

Let us propose the solution of the problem in order to analyze the given statements.

The problem must be solved with Newton's second law.

When he jumps off the plane

     fr - w = ma

Where the friction force has some form of type.

     fr = G v + H v²

Let's replace

     (G v + H v²) - mg = m dv / dt

We can see that the friction force increases as the speed increases

At the equilibrium point

      fr - w = 0

      fr = mg

      (G v + H v2) = mg

For low speeds the quadratic depended is not important, so we can reduce the equation to

     G v = mg

     v = mg / G

This is the terminal speed.

Now let's analyze the claims

a) False is g between the friction force constant

b) True.

c) False. It is equal to the weight

d) False. In the terminal speed the acceleration is zero

e) False. The friction force is equal to the weight

3 0
3 years ago
How large must the coefficient of static friction be between the tires and road, if a car rounds a level curve of radius 85 m at
tatuchka [14]

Answer:

0.66

Explanation:

By using the formula

u = v^2 / r g

Where u is coefficent of friction

u = 23.5 × 23.5 / (85 × 9.8)

u = 0.66

4 0
3 years ago
What is the term that describes waves that require a medium through which to travel?
gladu [14]

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

8 0
2 years ago
A solid cube of side 5cm has a mass of 250g. What is its density in kgm ??​
Mariulka [41]

Answer:

5kgm

Explanation:

convert cm to m and g to kg

250/1000=0.25kg

5/1000=0.05m

then find the density

density=mass/volume

=0.25kg/0.05m

=5kgm

7 0
2 years ago
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