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Darina [25.2K]
3 years ago
11

A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-

kg object be placed so as to experience a net force of zero from the other two objects?
Physics
1 answer:
djverab [1.8K]3 years ago
6 0

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}

\frac{3-y}{y}=\sqrt{\frac{7}{2}}

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

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Pachacha [2.7K]
When the car comes to a stop, the final velocity must be 0 m/s.
Since the car js decelerating in a forward direction, acceleration must be negative.

final v = initial v + a•t
0 = 20 + (-6)t
t = 3.33s
5 0
3 years ago
A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one
alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R=13\Omega

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper  wire=Sum of resistance of two piece of wires

r+7r=13

8r=13

r=\frac{13}{8}ohm

Resistance of long piece of wire=7\times\frac{13}{8}=\frac{91}{8}\Omega

Resistance of short piece of wire =\frac{13}{8}\Omega

Resistivity of wire and cross section area of wire remains same .

Let L be the total  length  of wire and L' be the length of short  piece of wire.

We know that

R=\frac{\rho L}{A}=\frac{\rho}{A}L=KL

\frac{R}{L}=K

Where K=\frac{\rho}{A}=Constant

Using the formula

\frac{13}{L}=\frac{\frac{13}{8}}{L'}

\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}

L'=\frac{L}{8}

Length of short piece of wire=L'=\frac{L}{8}

Length of long piece of  wire=L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L

% of length of short piece of   wire=\frac{\frac{L}{8}}{L}\times 100=12.5%%

The resistance of the short piece=\frac{13}{8}\Omega

The resistance of the long piece=\frac{91}{8}\Omega

8 0
3 years ago
The weight of a body is 147N. what is its mass?
barxatty [35]

<u>To find the mass, with only the weight</u>:

  ⇒ must consider the relationship between the mass and weight

     ⇒ (<em>in other words</em>) we must find the equation that has both the

         mass and weight

<u>Based on our physics knowledge, we know</u>:

 Weight=mass*gravitational_. acceleration

  • Weight: 147N
  • Gravitational Acceleration: 9.8 m/s²

<u>Now let's plug in the values, and solve</u>:

 147N = mass*9.8_.m/s^2\\mass = 15_.kg

<u>Answer: 15 kg</u>

Hope that helps!

<em>*as a note, if you use the gravitational acceleration as 10m/s², then the answer would be 14.7 kg</em>

5 0
2 years ago
A 513 g ball strikes a wall at 14.7 m/s and rebounds at 11.3 m/s. The ball is in contact with the wall for 0.038 s. What is the
Natasha_Volkova [10]

consider the velocity of the ball towards the wall as negative and away from the wall as positive.

m = mass of the ball = 513 g = 0.513 kg

v₀ =  initial velocity of the ball towards the wall before collision = - 14.7 m/s

v = final velocity of the ball away from the wall after collision = 11.3 m/s

t = time of contact with the wall = 0.038 sec

F = average force acting on the ball

using impulse-change in momentum equation , average force is given as

F = m (v - v₀)/t

inserting the values

F = (0.513) (11.3 - (- 14.7))/0.038

F = 351 N


5 0
3 years ago
A soccer player practices kicking the ball into the goal from halfway down the soccer field. The time it takes for the ball to g
yarga [219]
<h2>Soccer player practices kicking the ball </h2>

The player has 15 meters per second ( m/s ) average velocity of the ball. In order to calculate, we know that the formula of calculating the velocity is velocity = displacement / time.

A player practices kicking the ball into the goal from halfway down the soccer field. Half displacement will be considered which is 45 meters and time interval is given which is 3 seconds. By putting values in the formula v = d / t ( 45 / 3 ) = 15, we get 15 m / s average velocity.

3 0
3 years ago
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