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dybincka [34]
3 years ago
5

At the gas station the high price was $3.50

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer: percentage change of 98.8

Step-by-step explanation:

3.5/2.87 = 1.2

1.2-100 = - 98.8

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103,727,495 in a word form
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103,727,495 in word form is: one hundred three million, seven hundred twenty-seven thousand, four hundred ninety-five.
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3 years ago
The melt in your mouth chocolate factory is a rectangular building the distance across the front of the store is 294 feet the di
deff fn [24]

Answer:

The sign would be 784 ft. long.

Step-by-step explanation:

The sign would be painted across the total perimeter of the building.

- the distance across the front of the store is 294 feet

- the distance from the front to the back is one third of this distance = (1/3) × 294 = 98 ft.

The perimeter of a rectangular = 2(L + B)

L = length of the building = 294 ft.

B = Breadth of the building = 98 ft.

Perimeter of the chocolate factory that the Sign would be painted across = 2(294 + 98) = 784 ft.

Hope this Helps!!!

7 0
3 years ago
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An air conditioning system can circulate 470 cubic feet of air per minute. How many cubic yards of air can it circulate per​ min
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Answer:

17 yards/minute.

Step-by-step explanation:

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2 years ago
The prime factorization of 180X²Y? (PLEASE HELP)
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8 0
2 years ago
A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di
Doss [256]

Answer:

a) P [ Z > 70 ]  = 0.1075  or 10.75 %

b)  P [ Z < 60 ] = 0.1038   or  10.38 %

c)  P [ 55 ≤ Z ≤ 70 ] =  0.8882   or 88.82 %

Step-by-step explanation:

Normal Distribution  μ = 65    and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ]  =  (Z-μ) ÷ σ  ⇒   P [ Z > 70 ] = (70-65) ÷4     P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up  to 70 miles therefore  we have to subtract 1 -0,8925

P [ Z > 70 ]  = 0.1075  or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ]  = ( 60 - μ ) ÷  σ ⇒  P [ Z < 60 ] = (60-65)÷ 4    P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26  which area is 0.1038 so

P [ Z < 60 ] = 0.1038     10.38 %

c) P [ 55 ≤ Z ≤ 70]

For  point  Z = 70 or 1.25 (case a above)  P [ Z ≤ 70] = (70-65)÷4  

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70]  = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ]  = (55-65) ÷ 4     P [ Z ≥ 55 ] = -2.5  and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] =  0.8944 - 0.0062  = 0.8882

8 0
3 years ago
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