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1 year ago

The side of an equilateral triangle is given as 8 cm, correct to the nearest centimetre. What is the least possible length of it

s perimeter?

Mathematics

1 answer:

artcher [175]1 year ago

7 0

$\textsf {21 cm}$

$\textsf {If it is correct to the nearest centimeter, then the least side length}\\\textsf {would be 8 - 1 = 7 cm. }$

$\textsf {Then, the least possible perimeter would be :}$

$\mathsf {7 \times 3}$

$\textsf {21 cm}$

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Dimas [21]

Answer:

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Step-by-step explanation:

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Carry out the operation in the parentheses first:

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⇒ 3³ + 14.7 ÷ 7 - 4.8

⇒ (3 × 3 × 3) + 14.7 ÷ 7 - 4.8

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2 years ago

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Inga [223]

Answer: 88%

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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2 years ago

Please show me How to do this number

VARVARA [1.3K]

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3 years ago