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Jlenok [28]
2 years ago
14

Plz answer this I really need help

Mathematics
1 answer:
hjlf2 years ago
5 0
The firstone I guess I'm not that sure tbh

Hope it’s right
Best luck with your studying
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Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?
Lena [83]

Answer:

B

Step-by-step explanation:

Given 2 quantities that vary directly, then the graph must pass through the origin.

Nikiya's graph is the only one to do this ⇒ B



8 0
3 years ago
Read 2 more answers
Answer this 2(3^2 + 4^2) = ?
Vikentia [17]

Answer:

50

Step-by-step explanation:

2(3^2+4^2)=

3^2/(3x3) = 9

4^2/(4x4) = 16

9+16=25        

so.... rewritten it is

2(25)= or 2 x 25= 50

6 0
3 years ago
What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?
shepuryov [24]

Refine 2(4z-3-1)

= 2(4z-4)

Refine : 166 - 16 = 120

therefore:

2(z-4) = 120

Divide both sides by  2 :

\frac{2(z-4)}{2} =  \frac{120}{2}

4z-4 = 60

add 4  to both sides:

4z-4+4 = 60+4

4z = 64

Divide both sides by 4 :

\frac{4z}{4} =  \frac{64}{4}

z = 16

hope this helps!


8 0
2 years ago
Read 2 more answers
daniel's basketball team won 23 games and lost 8 games. Write the ratio of wins to losses in simplest form.
Soloha48 [4]
23:8 is the simplest form. However, you can put 5.75:2 or even 2.86/1 if you are looking for the absolute simplest
3 0
3 years ago
A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0
3 years ago
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