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Jlenok [28]
2 years ago
14

Plz answer this I really need help

Mathematics
1 answer:
hjlf2 years ago
5 0
The firstone I guess I'm not that sure tbh

Hope it’s right
Best luck with your studying
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Compute delta y/delta x for the interval [2,5], where y = 4x - 9.
Kamila [148]
We have to compute: Δ y / Δ x.
The interval is [ 2, 5 ] and y = 4 x - 9.
y 1 = 4 · 2 - 9 = 8 - 9 = - 1
y 2 = 4 · 5 - 9 = 20 - 9 = 11
Δ y / Δ x = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= ( 11 - ( - 1 ) ) / ( 5 - 2 ) = ( 11 + 1 ) / 3 = 12 / 3 = 4
Answer:
Δ y / Δ x = 4

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3 years ago
What is the value of x in the equation 3 = 2x? A. 2/3
Alexxandr [17]
3 divided by 2 is 1.5 so c
6 0
2 years ago
Read 2 more answers
A taxi service charges $4.50 to pick someone up and then $0.75 per mile during the ride.
Umnica [9.8K]
Part A : y=$0.75m+$4.50
Part B : $8.25
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2 years ago
Frog and Toad decided to meet. Their houses are 120 ft apart. They start hopping towards each other at a speed of 2 ft/min and 3
Alex787 [66]

Answer:

24

Step-by-step explanation:

no explanation, I'm very sorry!

8 0
2 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
2 years ago
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