<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
Answer:
-6<x<-9
Step-by-step explanation:
if x+9<0 and 2x>-12
x<-9
x>-6
X is smaller than -9 but greater than -6.
The solution is -6<x<-9
The two sides marked 7 are congruent.
Sides AC and AD are congruent.
Sides BC and ED are congruent.
By SSS, the triangles are congruent.
Also, angles BAC and EAD are congruent, so by SAS, the triangles are congruent.
Answer: A. yes, by either SSS or SAS
Answer:
B
Step-by-step explanation:
Given that ;
f(x)= x³
f(x)-4 = x³- 4
See attached graph using the graph tool
