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nignag [31]
2 years ago
13

Does the table represent a function? Why or why not?

Mathematics
1 answer:
Anestetic [448]2 years ago
8 0

The table does not represent a function because (c) No, because one x-value corresponds to two different y-values.

<h3>How to determine the true statement?</h3>

The table of values is given as:

X Y

3 1

4 3

5 2

6 5

6 6

From the table of values, we have:

Y = 5 and 6 when X = 6

A table of values that is a function would have a y value of each x value

Hence, the table does not represent a function because one x-value corresponds to two different y-values.

Read more about tables and functions at:

brainly.com/question/19515541

#SPJ1

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Among all right triangles whose hypotenuse has a length of 12 cm, what is the largest possible perimeter?
Veronika [31]

Answer:

Largest perimeter of the triangle =  

P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)

Step-by-step explanation:

We are given the following information in the question:

Right triangles whose hypotenuse has a length of 12 cm.

Let x and y be the other two sides of the triangle.

Then, by Pythagoras theorem:

x^2 + y^2 = (12)^2 = 144\\y^2 = 144-x^2\\y = \sqrt{144-x^2}

Perimeter of Triangle = Side 1 + Side 2 + Hypotenuse.

P(x) = x + \sqrt{144-x^2} + 12

where P(x) is a function of the perimeter of the triangle.

First, we differentiate P(x) with respect to x, to get,

\frac{d(P(x))}{dx} = \frac{d(x + \sqrt{144-x^2} + 12)}{dx} = 1-\displaystyle\frac{x}{\sqrt{144-x^2}}

Equating the first derivative to zero, we get,

\frac{dP(x))}{dx} = 0\\\\1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0

Solving, we get,

1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0\\\\x = \sqrt{144-x^2}}\\\\x^2 = 144-x^2\\\\x = \sqrt{72} = 6\sqrt{2}

Again differentiation P(x), with respect to x, using the quotient rule of differentiation.

\frac{d^2(P(x))}{dx^2} = \displaystyle\frac{-(144-x^2)^{\frac{3}{2}}-x^2}{(144-x)^{\frac{3}{2}}}

At x = 6\sqrt{2},

\frac{d^2(V(x))}{dx^2} < 0

Then, by double derivative test, the maxima occurs at x = 6\sqrt{2}

Thus, maxima occurs at x = 6\sqrt{2} for P(x).

Thus, largest perimeter of the triangle =  

P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)

7 0
3 years ago
20 points pleas help!!
Anna [14]

I think if I did it right it should be B

5 0
3 years ago
Read 2 more answers
The sum of two numbers is 6<br> The difference of the two numbers is 3<br> What are the two numbers.
stiv31 [10]

Answer:

4.5 and 1.5

Step-by-step explanation:

4.5+1.5=6

4.5-1.5=3(difference)

3 0
3 years ago
Read 2 more answers
GIVING OUT BRAINLIEST TO WHOEVER CAN PROVIDE THE CORRECT ANSWER !! Asap
saul85 [17]

Answer:

139.48

Step-by-step explanation:

cos(55)=80/x

80/cos(55)=x

4 0
3 years ago
Can someone help me plzz??
ki77a [65]

Answer:

(0,20)

Step-by-step explanation:

1) we can represent the situation as coordinates

lets have # of texts be "x" variable

lets have bill be "y" as the y variable is always the dependant variable and the cost of the phone bill is dependant upon the number of texts so

y=mx+b-slope-intercept form

coordinates: (50,25) and (100,30)

slope: (30-25)/(100-50)

5/50=1/10

hence slope=1/10

y=1/10x+b

substitute in a coordinate pair into this equation

25=50*1/10+b

25=5+b

b=20

hence y intercept is (0,20)

8 0
3 years ago
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