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3 years ago

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V(t)=2000e^-.35t At what rate's compute value falling after 3 years

1 answer:

Reil [10]3 years ago

4 0

Given the value of computer at t years
V(t) = 2000e^-.35t
The rate of the computer value falling is given by:
dv(t)/dt= 2000 x 0.35e^-0.25t= -700e^-0.35t
at t= 3years,
dv(t)/dt|t=3 =-700e^-0.35x3 = -245
The computer value falls at a rate of 245 after 3 years.

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