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Dvinal [7]
3 years ago
7

V(t)=2000e^-.35t At what rate's compute value falling after 3 years

Mathematics
1 answer:
Reil [10]3 years ago
4 0
Given the value of computer at t years
V(t) = 2000e^-.35t
The rate of the computer value falling is given by:
dv(t)/dt= 2000 x 0.35e^-0.25t= -700e^-0.35t
at t= 3years,
dv(t)/dt|t=3 =-700e^-0.35x3 = -245
The computer value falls at a rate of 245 after 3 years.
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kolbaska11 [484]

Answer:

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Step-by-step explanation:

Given:

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6 0
3 years ago
A 1.50 liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25oC. Without change in t
cricket20 [7]
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5 0
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katrin2010 [14]

Answer:

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4 0
3 years ago
Someonee helppp meee pleaseee
BARSIC [14]
8.3% is ur answer hope this helps 
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3 years ago
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<1=97°

steps:

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2 years ago
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