A pulley system is used in an auto repair shop to lift a 200 kg engine block 1.5 m out of a car. The lower pulley is attached di
1 answer:
You might be interested in
Answer:
Explanation:
means initial angular velocity, which is 0 rev/min
means final angular velocity, which is
t means time t= 3.20 s
one revolution is equivalent to 2πrad so the final angular velocity is:
= (2π/60) *2.513*10^{4} rad/s
= 2628.5 rad/s
so the angular acceleration, α will be:
α = 2628.5 rad/s / 3.20 s
so the rotational motion about a fixed axis is:
+ 2αΔTita where ΔTita is the angle in radians
so now find the ΔTita the subject of the formula
ΔTita =
Answer:
The time is 5.71 sec.
Explanation:
Given that,
Acceleration
Initial velocity = 24.0 m/s
We need to calculate the time
Using equation of motion
v = u+at[/tex]
Where, v = final velocity
u = inital velocity
t = time
a = acceleration
Put the value into the formula
Hence, The time is 5.71 sec.