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mars1129 [50]
2 years ago
9

A pulley system is used in an auto repair shop to lift a 200 kg engine block 1.5 m out of a car. The lower pulley is attached di

rectly to the engine block, and there are 8 strands of rope attaching the lower pulley to the upper pulley. The repairman pulls through 12 m of rope in the process of lifting the engine block. How much work is done during this process
Physics
1 answer:
Daniel [21]2 years ago
6 0

For a pulley system is used in an auto repair shop to lift a 200 kg engine block 1.5 m out of a car, work is done during this process is mathematically given as

w=3000J

<h3>What is the work is done?</h3>

Generally, the equation for work done is mathematically given as

W=mgh

Therefore

W=200*10*1.5

w=3000J

In conclusion, work done

w=3000J

Read more about work done

brainly.com/question/756198

#SPJ1

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List 3 different things you can read off a motion graph.
Lunna [17]

Answer:

1) Position time graph

2) Acceleration time graph

3) Velocity time graph

6 0
2 years ago
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Learning Goal: To understand the nature of a sound wave, including its properties: frequency, wavelength, loudness, pitch, and t
Lady_Fox [76]

Answer:

Sound wave is a longitudinal wave that propagates in a medium

Explanation:

<em>Part A:</em> (C) Sound wave is propagation of pressure fluctuations in a medium.

<em>Part B: </em>(C) Pressure fluctuations travel along the direction of propagation of         the sound wave.

<em>Part C: </em>(A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.

5 0
3 years ago
Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in
postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is \rho = \frac{m}{V}, and the volume of a pyramid is (confusingly written on the proposal) V=\frac{1}{3} Ah, so we can write:

m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h

Where s is the side of the base, being s^2 the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that \frac{1m}{100cm}=1, and we can use this factor to convert anything written in cm to anything written in m. Example:

500cm=500cm\frac{1m}{100cm}=5m

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so <em>it's not doing anything but changing the units</em>.

We can use this tool like this:

2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3

Where we have used the fact that 1^3=1 (<u>we can elevate any conversion factor to any number and they still will be 1</u>) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg

And now we will convert to short tons using two conversion factors at the same time:

m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0
2 years ago
a cylinder has a radius of 2.1cm and a length of 8.8cm .total charge 6.1 x 10^-7C is distributed uniformly throughout. the volum
7nadin3 [17]

The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × 10^{-1} C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 ×10^{-2} m

height (h) =8.8 cm = 8.8 ×10^{-2} m

total charge (q) =6.1×10^{-7} C

To solve:

volume charge density (ρ)

We know;

<u> ρ =q ÷ v</u>

volume of cylinder = π ×r  × r × h

volume of cylinder =3.14 × 2.1 × 2.1 ×10^{-4} × 8.8 ×10^{-2}

volume of cylinder (v) = 122.23 ×10^{-6}

<u> ρ =q ÷ v</u>

ρ = 6.1×10^{-7} ÷   122.23 ×10^{-6}

<u>ρ = 0.04 × </u>10^{-1}<u> C</u>

Therefore the volume charge density of a substance (ρ) is 0.04 × 10^{-1} C.

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3 years ago
Rate at which wave travels or propagates
Softa [21]

Answer:

v =fλ v = f λ where v

Explanation:

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