Answer:
Explanation:
An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.
Since there is no decimal point in the number given above, the counting for the number of the significant figures will start from the left. Then, the first zero from the left is insignificant. Therefore, in this number there are 6 significant figures.
A. Fnet=ma
6*2=12N of force acting on the object in the direction it is accelerating
B. Fnet=ma
4*2=8N of force action on the object in the direction it is accelerating
Answer:
3.2 m/s²
Explanation:
Acceleration can be calculated as:
v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time)
25 m/s = 9 m/s + a(5 s) (a is unknown)
16 m/s = a(5 s)
a = 3.2 m/s²
We assume that this is a uniform acceleration (meaning that the velocity increases at an equal rate for those 5 seconds).
Answer:
Explanation:
distance travelled
s = 2πR
= 2 X 3.14 X 140
= 880 m
final velocity = v
initial velocity = u
distance travelled = s
time = 60 s
s = ut + 1/2 at²
880 = .5 x a x 60²
a = .244 m/s²
final velocity v = at
= .244 x 60
= 14.66
centripetal acceleration at final moment
v² /R
14.66 X 14.66 / 140
= 1.53 m/s⁻²
1.53 m/s²
this is centripetal acceleration which acts towards the centre.
tangential acceleration calculated a _t = .244
redial acceleration ( centripetal ) = 1.53
Resultant acceleration
R²= 1.53² + .244 ²
R = 1.55 m/s²
total force = 1.55 x 76
= 118 N