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3 years ago

13

Sound is produced by

2 answers:

elena-14-01-66 [18.8K]3 years ago

7 0

Sound is produced when something <span>vibrates.

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zavuch27 [327]3 years ago

5 0

Vibrations it's produced

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An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in

Anestetic [448]

Answer:

The value is $a = 4.0 \ m/s^2$

Explanation:

From the question we are told that

The velocity is $a = 120 \ km/h = [tex]\frac{120 * 1000}{3600} = 33.3 \ m/s$ [/tex]

The time taken is $t = 8.28 \ s$

The time taken for contact is $t_c = 0.815 \ s$

The velocity of the of the car after contact is $v_c = 71.0 \ km/h = [tex]\frac{71 *1000}{3600} = 19.7 2 \ m/s$ [/tex]

From the equation of kinematics we have that

$v = u + at$

Here u = 0 \ m/s since the car is initially motionless

=> $33.3 = 0 + a * 8.28$

=> $a = 4.0 \ m/s^2$

4 0

3 years ago

What is the work required for a penguin to push a box 2 meters with a force of 8 newtons?

choli [55]

Work done is given by product of force and displacement due to that force

So here we will have

$Work = Force \times displacement$

here we know that

$Force = 8 N$

$displacement = 2 m$

Now work done is given as

$W = 8\times 2$

$W = 16 J$

so it will do 16 J work to move the box

3 0

3 years ago

An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro

svet-max [94.6K]

We can rearrange the mirror equation before plugging our values in.
1/p = 1/f - 1/q.
1/p = 1/10cm - 1/40cm
1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p <-- cross multiplication
13.33cm = p

Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'

So the height of the image produced by the mirror is 9.6cm.

6 0

3 years ago

A 45 N girl sits on a bench 0.6 meters off the ground. How much work is done on the bench?

ycow [4]

Answer: 27 joules

Explanation:

Work is done when force is applied on the bench over a distance. it is measured in joules.

Workdone = force x distance

= 45 N x 0.6 metres

= 27 joules

Thus, 27 joules of work is done on the bench.

6 0

3 years ago

Ilia_Sergeevich [38]

Answer:

The value is $C = 30729\ c$

Explanation:

From the question we are told that

The power rating of the stove is $P = 4.4 KW = 4.4 *10^{3} \ W$

The duration of its use everyday is $t_1 = 70 \ minutes = 1.167 \ hours$

The rating of the light bulbs is $P_2' = 150 W$

The number is $n = 7$

The power rating of the total bulb is $P_2 = 7 * 150 = 1050 \ W$

The duration of its use everyday is $t_2 = 7 hours$

The power rating of miscellaneous appliance $P_3 = 1.8 \ KW = 1.8 *10^{3} \ W$

The duration of its use everyday is $t_3 = 1 hour$

The power rating of hot water $P = 4 KW = 4 *10^{3} \ W$

The duration of its use everyday is $t_4 = 120 \ minutes = 2 hours$

Generally the total electrical energy used in 1 month is mathematically represented as

$E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30$

=> $E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30$

=> $E = 614598 \ W \cdot h$

=> $E = 614.6 \ K W \cdot h$

Generally the monthly electricity bill is mathematically represented as

$C = 614.6 * 50$

=> $C = 30729\ c$

8 0

2 years ago