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Gre4nikov [31]
3 years ago
5

Manufactured bolts can’t be too long or too short or they might not fit where they need to. Help determine which bolts will work

and which won’t. Show your work for all steps.
1. A machine makes bolts that are 12 mm long. The bolts are considered acceptable if they are within 0.2 mm of 12 mm.

a. What is the longest the bolt can be and still be acceptable?



b. What is the shortest the bolt can be and still be acceptable?
Physics
1 answer:
Sever21 [200]3 years ago
5 0
What is the longest the bolt can be and still be acceptable
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How can hypotheses best be tested
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In order for a hypothesis to be tested, and experiment needs to be designed.

Many trials need to be runned in order to get accurate results and to form a valid conclusion that can prove or disprove the hypothesis

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3 years ago
A computer monitor uses 200 W of power. How much energy does it use in 10 seconds?
gavmur [86]

Answer:

<u>The correct answer is 0.556 Watts</u>

Explanation:

The computer monitor uses 200 Watts of power in an hour, that is the standard measure.

If we want to know, how much energy the computer monitor uses in one second, we will have to divide both sides of the equation into 3,600.

1 hour = 60 minutes = 3,600 seconds (60 x 60)

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Therefore to calculate how much energy is used in 10 seconds, we do this:

Energy per second x 10

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<u>The computer monitor uses 0.556 Watts in 10 seconds</u>

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3 years ago
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A 75.0-kg man standing on a bathroom scale in an elevator. Calculate the scale in N, reading if the elevator moves upward at a c
Salsk061 [2.6K]

The scale in N, reading if the elevator moves upward at a constant speed of 1.5 m/s^2 is 862.5 N.

weight of man = 75kg

speed of elevator, a = 1.5 m/ s^{2}

F - w = ma \\

F = w + ma

F = m ( a +g )

F = 75 ( 1.5 + 10 ) \\

F = 75 ( 11.5 )

F = 862.5 N

So, the scale reading in the elevator is greater than his 862.5 N weight. This indicates that the person is being propelled upward by the scale, which it must do in order to do so, with a force larger than his weight. According to what you experience in quickly accelerating or slowly moving elevators, it is obvious that the faster the elevator acceleration, the greater the scale reading.

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8 0
2 years ago
Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an
8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 m/s^2 where as radial the component of acceleration is 8.77 m/s^2

Explanation:

As per the given data

u=π/4 rad

ω=u'=2 rad/s

α=u''=4 rad/s

r=e^u

So the transverse component of acceleration are given as

a_{\theta}=(ru''+2r'u')\\

Here

r=e^u\\r=e^{\pi/4}\\r=2.1932 m

r'=e^u.u'\\r'=2.1932 \times 2\\r'=4.3864 m

So

a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\

The transverse component of acceleration is 26.32 m/s^2

The radial component is given as

a_r=r''-r\theta'^2

Here

r''=e^u.u'^2+e^u u''\\r''=2.1932 \times (2)^2+2.1932\times 4\\r''=17.5456 m

So

a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2

The radial component of acceleration is 8.77 m/s^2

6 0
3 years ago
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