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ohaa [14]
2 years ago
7

Henry Bartholomew Dinglenut Anderson Quanlingling Dingleberry ate 300000 cookies. what does he have?

Mathematics
1 answer:
arlik [135]2 years ago
8 0

Henry Bartholomew Dinglenut Anderson Quanlingling Dingleberry after eating 300000 cookies will have: (A). DIabetes

<h3>Meaning of Diabetes</h3>

Diabetes can be defined as a  deadly disease that occurs due to the failure of the pancreas to produce insulin that is enough for the body or when the body is unable to put to use all the insulin it produces.

Insulin is a hormone that regulates sugar in the blood.

In conclusion, diabetes is a state of a body that has too much of sugar present in its blood.

Lean more about diabetes: brainly.com/question/864309

#SPJ1

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Step-by-step explanation:

1015

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The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and
antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.25, \sigma = 0.05

a. What is the probability that a single car of this model fails to meet the NOX requirement?

Emissions higher than 0.3, which is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.3 - 0.25}{0.05}

Z = 1

Z = 1 has a pvalue of 0.8417.

1 - 0.8413 = 0.1587.

15.87% probability that a single car of this model fails to meet the NOX requirement.

b. A company has 4 cars of this model in its fleet. What is the probability that the average NOX level of these cars are above 0.3 g/mi limit?

Now we have n = 4, s = \frac{0.05}{\sqrt{4}} = 0.025

The probability is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3 - 0.25}{0.025}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

4 0
3 years ago
Find the value of b. Round your answer to the nearest tenth.
marissa [1.9K]

Answer:

Side CA = 7.8

Step-by-step explanation:

<u>Given:</u>

Acute angled \triangle ABC.

\angle B =40^\circ

AB = 10

BC = 12

We can use cosine rule here to find the side AC = b

<em>Formula for cosine rule: </em>

cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

cos 40 = \dfrac{12^{2}+10^{2}-b^{2}}{2\times 12\times 10}\\\Rightarrow cos 40 = \dfrac{144+100-b^{2}}{240}\\\Rightarrow 0.77 = \dfrac{244-b^{2}}{240}\\\Rightarrow 244-b^{2} = 0.77 \times 240\\\Rightarrow 244-b^{2} = 183.85\\\Rightarrow 244-183.85 = b^{2}\\\Rightarrow b^2 = 60.15\\\Rightarrow b = 7.76

To the nearest tenth <em>b = 7.8</em>

8 0
3 years ago
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