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viktelen [127]
2 years ago
14

Find the y-intercept of the line through the points P(6, -6) and Q(8,-1)

Mathematics
1 answer:
Lorico [155]2 years ago
4 0

Answer:

(-21,0)

Step-by-step explanation:

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What is the sum of the interior angles of the polygon shown below?
34kurt

Answer:

900

Step-by-step explanation:

Sum of interior angle for a polygon = (n-2)180

7 sides

=(7-2)180

=5*180

=900

8 0
4 years ago
Please help! i need to find the mean
irina1246 [14]

Answer:

<h3>          The mean is 3.74</h3>

Step-by-step explanation:

\overline x =\dfrac{-3\cdot4+(-2)\cdot2+3\cdot1+4\cdot1+6\cdot4+8\cdot7}{4+2+1+1+4+7}\\\\\\\overline x =\dfrac{-12-4+3+4+24+56}{19}\\\\\\\overline x =\dfrac{71}{19}=3.7368421....\approx3.74

7 0
4 years ago
Help me please i am marking brainiest, no one ever helps me with anything i am really struggling as a kid to move on to the next
ExtremeBDS [4]
So assuming that the book is 100% the student has read 45% of the book so far in a time of 37 minutes so if you divide 45 by 37 you get 1 minute and 22 seconds per 1% of the assignment
If you multiply this by 100% you get 122 minutes for the total assignment
7 0
3 years ago
5 times 3/4 in a mixed number
Arte-miy333 [17]
5 x 3/4 = 15/4 

15/4 = 3 3/4
6 0
4 years ago
Graphing in Point-Slope Form y−y1=m(x−x1) <br> ​<br> Graph the equation y+7=−45(x−4) ?
nevsk [136]

Answer:

<h2>The graph is in the attachment.</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - a point on a line</em>

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept → (0, b)</em>

We have the equation in a point-slope form:

y+7=-\dfrac{4}{5}(x-4)

y-(-7)=-\dfrac{4}{5}(x-4)

Therefore we have one point: <em>(4, -7)</em><em>.</em>

<em>Convert to the slope-intercept form:</em>

y+7=-\dfrac{4}{5}(x-4)              <em>use the distributive property</em>

y+7=-\dfrac{4}{5}x+\left(-\dfrac{4}{5}\right)(-4)

y+7=-\dfrac{4}{5}x+\dfrac{16}{5}

y+7=-\dfrac{4}{5}x+3\dfrac{1}{5}          <em>subtract 7 from both sides</em>

y=-\dfrac{4}{5}x-3\dfrac{4}{5}

Put <em>x = -1</em><em> </em>to the equation:

y=-\dfrac{4}{5}(-1)-3\dfrac{4}{5}=\dfrac{4}{5}-3\dfrac{4}{5}=-3

Therefore we have the second point <em>(-1, -3)</em>.

3 0
4 years ago
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