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yKpoI14uk [10]
3 years ago
7

Look at the screen shot i need the answer pls its for my sis

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

Step-by-step explanation:

its bbvbbbbbbbbbbbb

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Solve for j. please help meee
Pepsi [2]

Answer:

112 degrees

Step-by-step explanation:

Angle J and the other angle combines to form a straight angle. In other words, they must total 180 degrees. Thus:

68+j=180

Subtract 68 from both sides:

j=112\textdegree

And we're done!

7 0
3 years ago
Read 2 more answers
Find dy/dx x=a(cost +sint) , y=a(sint-cost)​
MissTica

Answer:

\begin{aligned} \frac{dy}{dx} &= \frac{\cos(t) + \sin(t)}{\cos(t) - \sin(t)} \end{aligned} given that a \ne 0 and that \cos(t) - \sin(t) \ne 0.

Step-by-step explanation:

The relation between the y and the x in this question is given by parametric equations (with t as the parameter.)

Make use of the fact that:

\begin{aligned} \frac{dy}{dx} = \quad \text{$\frac{dy/dt}{dx/dt}$ given that $\frac{dx}{dt} \ne 0$} \end{aligned}.

Find \begin{aligned} \frac{dx}{dt} \end{aligned} and \begin{aligned} \frac{dy}{dt} \end{aligned} as follows:

\begin{aligned} \frac{dx}{dt} &= \frac{d}{dt} [a\, (\cos(t) + \sin(t))] \\ &= a\, (-\sin(t) + \cos(t)) \\ &= a\, (\cos(t) - \sin(t))\end{aligned}.

\begin{aligned} \frac{dx}{dt} \ne 0 \end{aligned} as long as a \ne 0 and \cos(t) - \sin(t) \ne 0.

\begin{aligned} \frac{dy}{dt} &= \frac{d}{dt} [a\, (\sin(t) - \cos(t))] \\ &= a\, (\cos(t) - (-\sin(t))) \\ &= a\, (\cos(t) + \sin(t))\end{aligned}.

Calculate \begin{aligned} \frac{dy}{dx} \end{aligned} using the fact that \begin{aligned} \frac{dy}{dx} = \text{$\frac{dy/dt}{dx/dt}$ given that $\frac{dx}{dt} \ne 0$} \end{aligned}. Assume that a \ne 0 and \cos(t) - \sin(t) \ne 0:

\begin{aligned} \frac{dy}{dx} &= \frac{dy/dt}{dx/dt} \\ &= \frac{a\, (\cos(t) + \sin(t))}{a\, (\cos(t) - \sin(t))} \\ &= \frac{\cos(t) + \sin(t)}{\cos(t) - \sin(t)}\end{aligned}.

4 0
3 years ago
!!!!! PLEASE HELP I'LL FOLLOW WHOEVER GETS IT RIGHT!!!!​
g100num [7]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
10 kids are randomly grouped into an A team with five kids and a B team with five kids. Each grouping is equally likely. (a) Wha
nikitadnepr [17]

Answer:

I think B is 1/5. I think C is 1/2.

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Write an expression based on description; use grouping symbols
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it's your answer and make me barinly least

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