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2 years ago

Which set of values could be the side lengths of a 30-60-90 triangle?

1 answer:

5 0

The correct answer is option B which is the set of values that could be the side lengths of a 30-60-90 triangle are (6,6√3, 12).

<h3>What is the right-angled triangle?</h3>

A triangle has three angles of 30-60 and 90 degrees in which the two sides are perpendicular to each other.

The three sides of the triangle will be calculated by applying the Pythagorean theorem:-

The sum of the square sides will be equal to the square of the third side.

For sides (6,6√3, 12)

12² = 6² + (6√3)²

144 = 36 + (36 x 3)

144 = 36 + 108

144 = 144

Therefore the correct answer is option B which is the set of values that could be the side lengths of a 30-60-90 triangle (6,6√3, 12).

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$\bold{\huge{\underline{ Solution\: 2 }}}$

The name of the circle is IJKL
The name of central Angle
$\sf{\underline{= {\angle} IHJ }}$
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${\bigstar}$ Circle :- It is a round figures, which has no end points.

${\bigstar}$ Central angle :- It the angle ,which lie in the middle of the circle.

Here, H is the mid point of the circle .So, Angle IHJ is the central angle.

${\bigstar}$ Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .

Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

$\bold{\huge{\underline{ Solution\: 3 }}}$

Semicircle = FGH and FIH
Minor Arc :- FG or GH
Major Arc :- FHG or GFH

${\bigstar}$ Semicircle :- Semicircle is nothing but the half of the circle.

Here, In second diagram 

FGH and FIH are acting as two semicircles which simulatineously forming one circle.

${\bigstar}$ Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.

Here, 

FG or GH are the minor arc of the given circle.

${\bigstar}$ Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.

Here, 

FHG or GFH is the major arc as it is larger than the semicircle of the given circle .

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2 years ago

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3 years ago

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Construct an inscribed circle in triangle PQR by finding the incenter of the triangle.

hodyreva [135]

Answer:

Check it below

Step-by-step explanation:

Hello!

By definition, the intercept of the 3 bisectors, within a triangle is the Incenter. So let's get started, by tracing three bisectors.

In the triangle PQR::

Use a compass, open its legs with a little more than half of $\overline{PQ}$ . Place the needle point in the vertex of P. Mark!
Do the same, placing the needle point in Q, following $\overline{QP}$ direction. Mark
Repeat it with the other triangle's line segment, namely: