3x + 4y = 16
-4x - 3y = -19
4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1
Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4
Answer:
x = 4
y = 1
I don't know I just need the points Lol sorry
The first answer is 25x + 45 = c
The second one is y=3x
Hopes this helps
Answer:
The positive numbers are 51 and 53
Step-by-step explanation:
Let first odd integer be x and another odd integer is (x+2).
According to the given condition,
The product of two positive consecutive odd integers is 2703 i.e.
x(x+2) = 2703

It is a quadratic equation. It can be solved as follows :
x = 51 and x = -53
Neglecting negative sign,
The first number = 51
Another number =(51+2) = 53
Hence, the positive numbers are 51 and 53.
At the end of the January the balance of credit card need to be $498+$35=$533
$533 is more than one half of the $900. So at the end of the January.