Write two fractions that name each point on the number line

Solve the equation -18=p/2?

sasho [114]

Answer:

p=-36

Step-by-step explanation:

-18=p/2

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Multiply both sides by 2

-18(2)= p/2 (2)

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-36 = p

switch the sides of the equation

______________________

p=-36

5 0

3 years ago

Read 2 more answers

Pls help, will give brainliest

Zinaida [17]

Answer:

Acute Triangle :))

8 0

3 years ago

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What is the equation of the line in slope intercept form? I WILL GIVE BRAINLY

irina [24]

Answer:

y=x+20

Step-by-step explanation:

The y-intercept is 20, as the line is on the y-axis while x is 0. The slope would be 0, because the y and x values both increase by 10, so 10/10 which simplifies to 1. The result would be y=10/10x + 20 simplifying to y=1x+20, which is y=x+20.

Hope this helps!

4 0

3 years ago

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Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

2 years ago

Two rectangles are similar. The length and width of the first rectangle are 12

Masja [62]

Answer:

scale factor = 1.2

Step-by-step explanation:

To determine the scale factor, calculate the ratio of the length of the second rectangle to the length of the first rectangle. The corresponding ratio of widths should also equal the same ratio.

scale factor = $\frac{14.4}{12}$ = $\frac{6}{5}$ = 1.2

4 0

3 years ago