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Rama09 [41]
3 years ago
15

HELP PLEASE PLEASE I WILL PUT 5 STARS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
yan [13]3 years ago
8 0
The answer would be A; males do not produce estrogen. 
Olin [163]3 years ago
5 0
The answer would be "c"
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Why cant atoms of one element convert to another element?
N76 [4]
They can be converted, it's called nuclear transmutation.
4 0
3 years ago
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Weather includes such conditions as air pressure, wind, _____, and moisture in the air.
Softa [21]

Answer:

Weather includes such conditions as air pressure, wind, <em><u>temp</u></em><em><u>erature</u></em><em><u> </u></em>, and moisture in the air.

7 0
3 years ago
This graph shows two curves pertaining to a hydrogen s orbital.
fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function  which is denoted by R_{nl}(r) shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as R^{2}_{nl}(r) shown in  blue  color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds  which has radial and angular nodes which will be represented by <em>'n'</em>.

It is observed that for any atomic orbital, the total number of nodes will be n-1  .


Considering the s orbital of the hydrogen, which has zero angular momentum  (l); (l=0), as it has zero angular nodes.  

Hence, there will be only radial nodes, which is

(n−1  =  total number of radial nodes in s orbitals)

According to the image, there are 4  radial nodes shown, so n  =  5  (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.


Answer 2) The radial nodes are observed in I'm seeing radial nodes at  

1.9a_{0},  6.4a_{0},13.9a_{0} and  27.0a_{0}.

where  a_{0} represents the  hydorgen bohr atomic radius =  0.0529177 nm


Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

3 0
3 years ago
Read 2 more answers
Calculate the solubility in g/l of lead (ii) fluoride in water at 25 oc if ksp of pbf2 is 4. 1 x 10-8.
Tems11 [23]

The solubility in g/l of lead (ii) fluoride in water at 25°C if ksp of PbF2 is 4. 1 x 10-8. is 5.3 ×10^(-1).

When PbF₂ dissolves, it dissociates as follows;

PbF₂ --> Pb²⁺ + 2F⁻

If molar solubility of PbF₂ is x, then molar solubility of Pb²⁺ is x and F⁻ is 2x.

ksp is solubility product constant and it can be calculated as follows;

ksp = [Pb²⁺][F⁻]²

ksp = (x)(2x)²

ksp = 4x³

4_{X} ^{3} = 4.1 * 10^{-8}\\\\ X^{3}  = 1.025 * 10^{-8}\\\\ X =  0.092 * 10^{-3}\\ \\X = 2.1 * 10^{-3}

To calculate solubility in terms of g/L, we have to know the molar mass of PbF₂.

Solubility of PbF₂ is 2.1 * 10^{-3} mol/L x 248 g/mol = 5.14 * 10^{-1} g/L

Thus, we concluded that the solubility of given solution is 5.14 × 10^(-1). which is approx 5.3 × 10^(-1).Hence option D is the correct option.

Learn more about solubility: brainly.com/question/14366471

#SPJ4

6 0
2 years ago
Select the correct answer.
cupoosta [38]

Answer:

A.

as the sum of the energy of the products and the energy of the reactants.

Explanation:

Because the sun is on top of the energy.

3 0
3 years ago
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