Answer:
0.086
Explanation:
The formula for calculating the fraction of a covalent bond can be expressed as:
= exp (-0.25ΔE²)
![= exp[-0.25(E_{Al}-E_{p})^2]---(1)](https://tex.z-dn.net/?f=%3D%20exp%5B-0.25%28E_%7BAl%7D-E_%7Bp%7D%29%5E2%5D---%281%29)
from the equation above;
= the electronegativity of aluminum
= electronegativity of phosphorus
Using the data from periodic table figures;
= 1.5
= 2.1
∴
fraction of the covalent = exp[-0.25(1.5 - 2.1)²]
fraction of the covalent = exp(-0.09)
fraction of the covalent = 0.914
Now, the fraction of ionic bond will be = 1 - the fraction of covalent bond
= 1 - 0.914
∴
the fraction of bond that is ionic = 0.086
This is one of the ideal gas laws. Presumably the pressure remains the same so it is not part of the givens.
Formula
V / T = V1 / T1
Givens
- V = 56.05 mL
- T = 315.1 degrees Kelvin
- V1 = x
- T1 = 380.5 degrees Kelvin
Solution
56.05/315.1 = x/380.5 Simplify the left.
0.1779 = x / 380.5 Multiply both sides by 380.5
0.1779 * 380.5 = 380.5x/380.5
67.68 mL = x This is your answer
Creo que la respuesta es <span>Iones positivos y una nube de electrones. </span>
<h3><u>Answer and explanation</u>;</h3>
- <em><u>The isotope U-235 is an important common nuclear fuel because under certain conditions it can readily be split, yielding a lot of energy. It is therefore said to be 'fissile' and use the expression 'nuclear fission'.</u></em>
- <em><u>Uranium 238 on the other hand is not fissionable by thermal neutrons, but it can undergo fission from fast or high energy neutrons. Hence it is not fissile, but it is fissionable.</u></em>
- In a nuclear power station fissioning of uranium atoms replaces the burning of coal or gas. Heat created by splitting the U-235 atoms is then used to make steam which spins a turbine to drive a generator, producing electricity.
