Answer:
2K + 2H₂O → 2KOH + H₂
Explanation:
The reactants are:
Potassium metal = K
Water = H₂O
The products are:
Potassium hydroxide = KOH
Hydrogen gas = H₂
The reaction equation is given as;
Reactants → Products
2K + 2H₂O → 2KOH + H₂
The reaction is a single displacement reaction
Explanation:
Elements of group 1A are known as alkali metals. Elements of this group are lithium, sodium, potassium, rubidium, cesium, and francium.
All these elements are metals and every element of this group has 1 valence electron. So, in order to attain stability they will readily lose their valence electron.
Hence, elements of group 1A are very reactive.
On the other hand, elements of group 7A are also known as halogen group. Elements of this group are fluorine, chlorine, bromine, iodine, and astatine.
All these elements are non-metals and every element of this group has 7 valence electrons. So, in order to completely fill their octet these elements gain 1 electron from a donor atom.
Therefore, these elements are alo reactive in nature.
But the major difference between elements of group 1A and group 7A is that elements of group 1A are metals but elements of group 7A are non-metals.
The answer is 39.948 g/mol so rounded to the nearest ones would be 40.00 g/mol.
Answer:
0.89 moles of N2 gas
Explanation:
From Avogadro's law:
V1/n1 = V2/n2
n2 = V2n1/V1
V1=11.2L
V2= 20L
n1=0.5 moles
n2 = ??
Therefore
n2= 20×0.5/11.2= 0.89 moles
