Answer:
C. 548mL
Explanation:
Attached is an image of the explanation. Hope this helps!
Answer:
0.471 mol/L
Explanation:
First, we'll begin by by calculating the number of mole of KMnO4 in 26g of KMnO4.
This is illustrated below:
Molar Mass of KMnO4 = 39 + 55 + (16x4) = 39 + 55 + 64 = 158g/mol
Mass of KMnO4 from the question = 26g
Mole of KMnO4 =?
Number of mole = Mass/Molar Mass
Mole of KMnO4 = 26/158 = 0.165mole
Now we can obtain the concentration of KMnO4 in mol/L as follow:
Volume of the solution = 350mL = 350/1000 = 0.35L
Mole of KMnO4 = 0.165mole
Conc. In mol/L = mole of solute(KMnO4)/volume of solution
Conc. In mol/L = 0.165mol/0.35
conc. in mol/L = 0.471mol/L
There is no photo , so I can’t really tell you the answer .
<u>Answer:</u> The nuclear binding energy of the given element is 
<u>Explanation:</u>
For the given element 
Number of protons = 3
Number of neutrons = (6 - 3) = 3
We are given:

M = mass of nucleus = 
![M=[(3\times 1.00728)+(3\times 1.00866)]=6.04782amu](https://tex.z-dn.net/?f=M%3D%5B%283%5Ctimes%201.00728%29%2B%283%5Ctimes%201.00866%29%5D%3D6.04782amu)
Calculating mass defect of the nucleus:
![\Delta m=M-A\\\Delta m=[6.04782-6.015126)]=0.032694amu=0.032694g/mol](https://tex.z-dn.net/?f=%5CDelta%20m%3DM-A%5C%5C%5CDelta%20m%3D%5B6.04782-6.015126%29%5D%3D0.032694amu%3D0.032694g%2Fmol)
Converting this quantity into kg/mol, we use the conversion factor:
1 kg = 1000 g
So, 
To calculate the nuclear binding energy, we use Einstein equation, which is:

where,
E = Nuclear binding energy = ? J/mol
= Mass defect = 
c = Speed of light = 
Putting values in above equation, we get:

Hence, the nuclear binding energy of the given element is 
Answer: That is true my friend.
Explanation:
Maybe not all substances but it can dissolve more than any other liquid.