9. -7/12
10. -2.75
11. 1.844
12. 4.539
Answer:
4/2+ 8/2+20/5+20/5+48/5+42/4
12/2+88/5+42/4
(120+ 352+210)/20= 682/20= 341 x 1/10=34.1
It is 350% I think, because you are trying to find how many groups of 2 go into 7. So, you have to divide 7 by 2. You get 3.5. 3.5 in percentage form is 350%
Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
