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3 years ago

Type the correct answer in the box

Mathematics

1 answer:

algol133 years ago

5 0

c = cost of food/med for cats

d = cost of food/med for dog

y = total cost/spent

What you know:

y = 6c + d [has 6 cats and 1 dog]

c = 2/3d - 5 [cost for cat is 5 less than 2/3 cost for dog]

y = $195

y = 6c + d

Substitute/plug in what you know, plug in (2/3d - 5) for c and 195 for y

195 = 6(2/3d - 5) + d Distribute/multiply 6 into (2/3d - 5)

195 = 4d - 30 + d Combine like terms

195 = 5d - 30 Add 30 on both sides of the equation

225 = 5d Divide 5 on both sides

$45 = d

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Solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: $\frac{4-5i}{2+3i}$

Multiplying and dividing by 2-3i

$=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

#learnwithBrainly

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