Write the equation of a line through points (5,5) and (1, 0) in point-slope form?
1 answer:
Answer:
Step-by-step explanation:
I’m assuming that the equation is to be written in slope intercept form (y=mx+b), so for this, you want to find the slope and y-intercept. To find the slope, use the equation in picture 1.
0 - 5 = -5
1 - 5 = -4
-5 / -4 = 1.25
So m, or the slope, is equal to 1.25.
To find the y-intercept, make a table like the second picture. Choose one of the ordered pairs as the given. I used 1,0.
0,?
1,0
Now find the change in x, which in this case, is 1. Then set up something like picture three.
1.25/1 = ?/1
?=1.25
Now backtrack to get:
0, -1.25
1, 0
Now we know what is y when x is 0, we know the y intercept and can make the equation:
y = 1.25x - 1.25
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Answer: 5y + 4x = - 10
Step-by-step explanation:
Two lines are said to be perpendicular if the product of their gradients = -1.
If the gradient of the first line is and the gradient of the second line is
, if the lines are perpendicular, them
x
= -1 , that is
=
The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.
The equation in slope -intercept form is given as :
y =mx + c , where m is the slope and c is the y - intercept.
Writing the equation in this form , we have
5x - 4y = + 3
4y = 5x -+3
y = 5x/4 + 3/4
comparing with the equation y = mx + c , then = 5/4
Which means that = -4/5 and the line passes through the point ( -5 , 2 ).
Using the equation of line in slope - point form to find the equation of the line;
y - = m ( x -
)
y - 2 = -4/5 ( x +5)
5(y - 2 ) = -4 ( x + 5 )
5y - 10 = -4x - 20
5y + 4x = - 10