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Elena-2011 [213]
2 years ago
14

At the start of a journey a milometer in a car shows 43562 and at the end of the journey the distance

Mathematics
1 answer:
Natali5045456 [20]2 years ago
7 0

The upper bound is 267.9 and the lower bound is 226.1.

<h3>What is the upper and lower bound?</h3>

At the beginning of the journey, the possible values of the milometer before been rounded to the nearest mile are: 43,561.5, 43,561.6, 43,561.7, 43,561.8, 43,561.9, 43,562,43,562.1, 43,562.2, 43,562.3, 43,562.4

At the end of the journey, the possible values of the milometer before been rounded to the nearest mile are: 43,828.5, 43,828.6, 43,828.7, 43,828.8, 43,828.9, 43829, 43829.1, 43829.2, 43829.3, 43829.4.

Upper bound =  43,829.4- 43,561.5 = 267.9

Lower bound = 43,828.5 - 43,562.4 = 226.1

To learn more about subtraction, please check: brainly.com/question/854115

#SPJ1

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the area of a reactangle mirror is 11 11/16 square feet the width of the mirror is 2 2/4 feet. if there is a 5 foot tall space o
77julia77 [94]
So square feet is area which is legnth times width or area=lw or a=lw

width=w=2 2/4
2/4=1/2
w=2 1/2=5/2

a=lw
11 11/16=187/16
187/16=l(5/2)

multiply both sides by 2/5 to clear the fraction (1/2 times 2/1=2/2=1)

374/80=legnth
simplify
374/80=187/40=4 27/40=legnth

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8 0
4 years ago
Combine like terms.
wolverine [178]
The answer is b




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8 0
3 years ago
Which graph shows the solution to this system of inequalities?<br><br> y&lt;-1/3x+1<br> y&lt;_2x-3
kari74 [83]

The graph that shows the solution to the system of inequalities is: C (see the image attached below).

<h3>How to Determine the Graph of the Solution to a System of Inequalities?</h3>

Given the following systems of inequalities:

y < -1/3x + 1

y ≤ 2x - 3

Below are the features of the graph that represents a solution to the system of inequalities:

  • The boundary line of y < -1/3x + 1 would be a dashed line and the shaded area would be below it, because of the inequality sign, "<".
  • The boundary lines of y ≤ 2x - 3 would be a solid line and the shaded area would be below it, because of the inequality sign, "≤".
  • The slope of the shaded line that represents  y < -1/3x + 1, would be -1/3, and the line would be a decreasing line which intersects the y-axis at 1.
  • The slope of the line that represents y ≤ 2x - 3, would be 2, and the line would also be an increasing line that intersects the y-axis at -3.

Therefore, the graph that shows the solution to the system of inequalities is: C (see the image attached below).

Learn more about the graph of the system of inequalities on:

brainly.com/question/10694672

#SPJ1

8 0
1 year ago
Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an
Gelneren [198K]

Answer:

(a) P (<em>Z</em> < 2.36) = 0.9909                    (b) P (<em>Z</em> > 2.36) = 0.0091

(c) P (<em>Z</em> < -1.22) = 0.1112                      (d) P (1.13 < <em>Z</em> > 3.35)  = 0.1288

(e) P (-0.77< <em>Z</em> > -0.55)  = 0.0705       (f) P (<em>Z</em> > 3) = 0.0014

(g) P (<em>Z</em> > -3.28) = 0.9995                   (h) P (<em>Z</em> < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, X \sim N (\mu, \sigma^{2}), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean.  The <em>z</em>-scores are standardized scores.

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

(a)

Compute the value of P (<em>Z</em> < 2.36) as follows:

P (<em>Z</em> < 2.36) = 0.99086

                   ≈ 0.9909

Thus, the value of P (<em>Z</em> < 2.36) is 0.9909.

(b)

Compute the value of P (<em>Z</em> > 2.36) as follows:

P (<em>Z</em> > 2.36) = 1 - P (<em>Z</em> < 2.36)

                   = 1 - 0.99086

                   = 0.00914

                   ≈ 0.0091

Thus, the value of P (<em>Z</em> > 2.36) is 0.0091.

(c)

Compute the value of P (<em>Z</em> < -1.22) as follows:

P (<em>Z</em> < -1.22) = 0.11123

                   ≈ 0.1112

Thus, the value of P (<em>Z</em> < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < <em>Z</em> > 3.35) as follows:

P (1.13 < <em>Z</em> > 3.35) = P (<em>Z</em> < 3.35) - P (<em>Z</em> < 1.13)

                            = 0.99960 - 0.87076

                            = 0.12884

                            ≈ 0.1288

Thus, the value of P (1.13 < <em>Z</em> > 3.35)  is 0.1288.

(e)

Compute the value of P (-0.77< <em>Z</em> > -0.55) as follows:

P (-0.77< <em>Z</em> > -0.55) = P (<em>Z</em> < -0.55) - P (<em>Z</em> < -0.77)

                                = 0.29116 - 0.22065

                                = 0.07051

                                ≈ 0.0705

Thus, the value of P (-0.77< <em>Z</em> > -0.55)  is 0.0705.

(f)

Compute the value of P (<em>Z</em> > 3) as follows:

P (<em>Z</em> > 3) = 1 - P (<em>Z</em> < 3)

             = 1 - 0.99865

             = 0.00135

             ≈ 0.0014

Thus, the value of P (<em>Z</em> > 3) is 0.0014.

(g)

Compute the value of P (<em>Z</em> > -3.28) as follows:

P (<em>Z</em> > -3.28) = P (<em>Z</em> < 3.28)

                    = 0.99948

                    ≈ 0.9995

Thus, the value of P (<em>Z</em> > -3.28) is 0.9995.

(h)

Compute the value of P (<em>Z</em> < 4.98) as follows:

P (<em>Z</em> < 4.98) = 0.99999

                   ≈ 0.9999

Thus, the value of P (<em>Z</em> < 4.98) is 0.9999.

**Use the <em>z</em>-table for the probabilities.

3 0
3 years ago
PLEASSSEEEE HELLLLP MEEEE!
Vanyuwa [196]

Answer:

1) C = 3

2) B = 5

3) C = 8

Step-by-step explanation:

Question 1)

We have:

(2x+3)(4x-1)

Distribute:

=(2x+3)(4x)+(2x+3)(-1)

Distribute:

=8x^2+12x-2x-3

Combine like terms:

=8x^2+10x-(3)

Therefore, C = 3.

Question 2)

We have:

(x+2) (2x^2+x-1)

Distribute:

\displaystyle =(x+2)(2x^2)+(x+2)(x)+(x+2)( - 1)

Distribute:

=(2x^3+4x^2)+(x^2+2x)+(-x -2)

Combine like terms:

=2x^3+(5)x^2+x-2

Therefore, B = 5.

Question 3)

We have:

(x+2)(x^2-3x-2)

Distribute:

=(x+2)(x^2)+(x+2)(-3x)+(x+2)(-2)

Distribute:

=(x^3+2x^2)+(-3x^2-6x)+(-2x-4)

Combine like terms:

=x^3-x^2-(8)x-4

So, C = 8.

6 0
3 years ago
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