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ivann1987 [24]
2 years ago
15

Find the area of the shaded region round to the nearest tenth

Mathematics
1 answer:
Alenkinab [10]2 years ago
6 0

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right).

Using the formula A=\frac{1}{2} ab \sin C, we get the area of the triangle is \frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}).

So, the area of the shaded sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}

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$6.75 I THINK

Step-by-step explanation:

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Write the equation of a circle whose center is at (3,-2) and has a radius of 11.<br>Show your work!
Viefleur [7K]

Answer:

(x - 3)^{2} + (y + 2)^{2} = 121

Step-by-step explanation:

The equation of a circle has the following format:

(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}

In which r is the radius and the centre is the point (x_{0}, y_{0})

In this question:

Center at (3,-2), so x_{0} = 3, y_{0} = -2

Radius 11, so r = 11

Then

(x - 3)^{2} + (y - (-2))^{2} = 11^{2}

(x - 3)^{2} + (y + 2)^{2} = 121

3 0
3 years ago
A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

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3 years ago
F.ree POINTS! . . .. ..
Xelga [282]
Answer:
oh thank you!
i hope you have a good day/night
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2 years ago
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