The YMCA lap pool is a right rectangular prism

Mathematics

2 answers:

serg [7]3 years ago

7 0

Answer:

<u>2 Meters deep.</u>

Step-by-step explanation:

If you multiply 36.8 m by 20m, you would get the base area of 736 m^2. If you divide that by 1472, you would get 2 meters deep.

Rasek [7]3 years ago

6 0

To find the depth (aka "height") you must use the volume formula

Volume = length x width x height

In this case:

The amount of water the pool can contain will equal to the volume

Volume = 1,472 m

length = 36.8 m

width = 20 m

height = unknown (let's make this h)

^^^Plug these numbers into the formula given above

1,472 = 36.8 x 20 x h

1,472 = 736h

Isolate h by dividing 736 to both sides

1,472/736 = 736h/736

This pool is 2 meters deep

Hope this helped!

~Just a girl in love with Shawn Mendes

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Rus_ich [418]

Check the picture below, so the hyperbola looks more or less like that.

based on the provided vertices, its center is at the origin, as you see there, the "a" component or traverse axis is 4, the "c" distance is 5.

$\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h, k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------$

$\bf \begin{cases}
h=0\\
k=0\\
c=5\\
a=4
\end{cases}\implies \cfrac{(y-0)^2}{4^2}-\cfrac{(x-0)^2}{b^2}=1
\\\\\\
\stackrel{c}{5}=\sqrt{4^2+b^2}\implies 5^2=16+b^2\implies 25=16+b^2
\\\\\\
9=b^2\implies \sqrt{9}=b\implies \boxed{3=b}
\\\\\\
\cfrac{(y-0)^2}{4^2}-\cfrac{(x-0)^2}{3^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{9}=1$