An example of a two dimensional object is a price of paper or a drawn figure on a paper because it has no height or depth
Step-by-step explanation:
mp=$30
%D=10%=%D=D/M.p×100
10%=D/30$×100=100D=10
DISCOUNT =$3
S.P=$27×6÷100=$1.62+27
<h3> =$28.62</h3>
Answer:
The answer is 3
Step-by-step explanation:
Answer:
(A) 0.377,
(B) 0.000,
(C) 0.953,
(D) 0.047
Step-by-step explanation:
We assume that having a bone of intention means not liking one's Mother-in-Law
(A) P(all six dislike their Mother-in-Law) = (85%)^6 = (.85)^6 = 0.377
(B) P(none of the six dislike their Mother-in-Law) =
(100% - 85%)^6 =
0.15^6 =
0.000
(C) P(at least 4 dislike their Mother-in-Law) =
P(exactly 4 dislike their Mother-in-Law) + P(exactly 5 dislike their Mother-in-Law) + P(exactly 6 dislike their Mother-in-Law) =
C(6,4) * (.85)^4 * (1-.85)^2 + C(6,5) * (.85)^5 * (.15)^1 + C(6,6) * (.85)^6 = (15) * (.85)^4 * (.15)^2 + (6) * (.85)^5 * .15 + (1) * (.85)^6 =
0.953
(D) P(no more than 3 dislike their Mother-in-Law) =
P(exactly 0 dislikes their Mother-in-Law) + P(exactly 1 dislikes her Mother) + P(exactly 2 dislike their Mother-in-Law) + P(exactly 3 dislike their Mother-in-Law) =
C(6,0) * (.85)^0 * (.15)^6 + C(6,1) * (.85)^1 * (.15)^5 + C(6,2) * (.85)^2 * (.15)^4 + C(6,3) * (.85)^3 * (.15)^3 =
(1)(1)(.15)^6 + (6)(.85)(.15)^5 + (15)(.85)^2 *(.15)^4 + (20)(.85)^3 * (.15)^3 =
0.047
Answer: 37, 38, and 39
Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.
3 consecutive integers can be represented as followed.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since the sum of our 3 consecutive integers is 114, we can set up an equation to represent this.
X + X + 1 + X + 2 = 114
We can simplify on the left side by combining the X's and the numbers.
3x + 3 = 114
-3 -3 ← <em>subtract 3 from both sides of the equation</em>
3x = 111
÷3 ÷3 ← <em>divide both sides of the equation by 3</em>
<em> </em>X = 37
X ⇒ <em>first integer = 37</em>
X + 1 ⇒ <em>second integer = 38</em>
X + 2 ⇒ <em>third integer = 39</em>
<em />
<em>Therefore, our 3 consecutive integers are 37, 38, and 39.</em>
