1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julia-pushkina [17]
2 years ago
7

NO LINKS!!!

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
3 0

Answer:

The 6 names to circle are:

  1. Laverna
  2. Alfonso
  3. Autumn
  4. Ignacio
  5. Kathyrn
  6. Lawrence

The underlined letters from those circled names are:

  1. RN
  2. ON
  3. TU
  4. G
  5. RN
  6. WR

The letters form the phrase \underline{\text{WR}}\ \underline{\text{ON}} \ \underline{\text{G}} \ \ \ \ \ \  \underline{\text{TU}} \ \underline{\text{RN}}  or "wrong turn". The spacing is done like that in the first version to show the various subgroups of letters.

Unfortunately the mentioned riddle at the bottom is cut off, so I don't know what the riddle is.

======================================================

Explanation:

  1. Laverna is correct because a translation is applied. "Translation" in geometry settings means "shifting up/down/left/right". In this case, triangle JKL is shifted 5 units right and 3 units up.
  2. Alfonso is correct. If a figure is labeled ABCD going in clockwise orientation, then a translation will preserve said orientation. The orientation only flips when a reflection occurs.
  3. Autumn is correct. Why? Because reflections are isometries, meaning they preserve distances and lengths and angles. In other words, the two triangles are twin clones of each other.
  4. Willa is not correct. The prime notations go on the image and NOT the preimage. In other words, the prime notations go for the "after" and not the "before". Example: triangle JKL in Laverna's diagram is the preimage, while J'K'L' is the image. JKL is "before", and J'K'L' is "after".
  5. Ignacio is correct. The figure enlarges or shrinks (depending on the scale factor if its larger than 1, or smaller than 1). The orientation stays the same. Refer to Alfonso's scenario where I mentioned the orientation flipping only when a reflection happens.
  6. Napoleon is incorrect. A reflection ALWAYS changes the orientation. Consider a triangle ABC where the motions from A to B to C goes clockwise. A reflection will flip the orientation to make A to B to C go counterclockwise. Example: Reflections over non-horizontal lines swap the positions of left vs right, which is another way to see why the orientation swaps as well.
  7. Kathyrn is correct assuming no reflection operations are done.
  8. Titus is not correct. A rotation is not the same as a reflection. Though I should point out that two reflections simplify to a rotation. The mirror lines must intersect in some way. Parallel mirror lines will have two reflections lead to a translation.
  9. Lawrence is correct. The order P,Q,R is clockwise, and so is the order P', Q', R'. A rotation preserves orientation. In this case, a 180 degree rotation has been done. The rule for that is any (x,y) point turns into (-x,-y).

Here's a summary table:

\begin{array}{|c|c|} \cline{1-2}\text{Student} & \text{Are They Correct?}\\\cline{1-2}\text{Laverna} & \textbf{Yes}\\\cline{1-2}\text{Alfonso} & \textbf{Yes}\\\cline{1-2}\text{Autumn} & \textbf{Yes}\\\cline{1-2}\text{Willa} & \text{No}\\\cline{1-2}\text{Ignacio} & \textbf{Yes}\\\cline{1-2}\text{Napoleon} & \text{No}\\\cline{1-2}\text{Kathyrn} & \textbf{Yes}\\\cline{1-2}\text{Titus} & \text{No}\\\cline{1-2}\text{Lawrence} & \textbf{Yes}\\\cline{1-2}\end{array}

Put another way, here are the people to circle (i.e. the people who made true statements):

  1. Laverna
  2. Alfonso
  3. Autumn
  4. Ignacio
  5. Kathyrn
  6. Lawrence

In the order presented above, the letters underlined are:

  1. RN
  2. ON
  3. TU
  4. G
  5. RN
  6. WR

Through a bit of trial and error, the letters make the phrase of:

\underline{\text{WR}}\ \underline{\text{ON}} \ \underline{\text{G}} \ \ \ \ \ \  \underline{\text{TU}} \ \underline{\text{RN}}

I'm not sure what to do with the extra "RN". It might be a typo, or it might be the case your teacher wants you to ignore repeats like this.

You might be interested in
Find the zeros of the function y=x^2-36​
Juliette [100K]

Answer:

x=6,-6

Step-by-step explanation:

6 0
3 years ago
Given m/n find the value of x if (x-3) and if (8x +3 )
Tpy6a [65]

Answer:

x= 8 Step-by-step explanation:

6 0
2 years ago
The volume of a right circular cone is found using the equation V = 1 3 π r 2 h . Which equation represents the volume solved fo
alex41 [277]

Solving for a variable in an equation means, we are changing the subject of formula of the equation.

The equation of r is: \mathbf{r = \sqrt{\frac{3V}{\pi h}}}

The equation is given as:

\mathbf{V = \frac 13 \pi r^2h}

We start by multiplying both sides by 3

\mathbf{V \times 3= \frac 13 \pi r^2h \times 3}

Rewrite as:

\mathbf{3V= \pi r^2h}

Divide both sides by \mathbf{\pi h}

\mathbf{\frac{3V}{\pi h}= \frac{\pi r^2h}{\pi h}}

Cancel out common factors

\mathbf{\frac{3V}{\pi h}= r^2}

Take square roots of both sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}}

Evaluate the right-hand sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= r}

Make r the subject

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Hence, the resulting equating for r is:

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Read more about the subject of formulas at:

brainly.com/question/21866313

6 0
3 years ago
Help me please &lt;3<br><br> place &lt;,&gt;, or = in the blank <br> 17/2 ________√70
Georgia [21]

Answer:

>

Step-by-step explanation:

17/5 is 8.5 but √70 is 8.3 something that for 17/2>√70

7 0
3 years ago
The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det
seraphim [82]

Answer:

The required hypothesis to test is H_0: \mu\leq 30 and H_1: \mu>30.

Step-by-step explanation:

Consider the provided information.

It is given that the nightclub has recently surveyed a random sample of n = 250 customers of the club.

She would now like to determine whether or not the mean age of her customers is over 30.

Null hypotheses is represents as H_0. Thus the null hypotheses is shown as:

H_0: \mu\leq 30

The alternative hypotheses is represents as H_1. Thus the alternative hypotheses is shown as:

H_1: \mu>30

Hence, the required hypothesis to test is H_0: \mu\leq 30 and H_1: \mu>30.

8 0
3 years ago
Other questions:
  • What =x in 1/4x+7=31/4
    9·1 answer
  • Find the value of: <img src="https://tex.z-dn.net/?f=%281-%5Cfrac%7B1%7D%7B2%5E2%7D%29%281-%5Cfrac%7B1%7D%7B3%5E2%7D%29...%281-%
    9·2 answers
  • The ledger of Novak Corp. on March 31 of the current year includes the selected accounts below before adjusting entries have bee
    13·1 answer
  • What's the lenght of side b in the figure below
    13·1 answer
  • What is the image of point (4, 3) if the rotation is 90º ? Please and thank you.
    13·1 answer
  • When we are approximating an irrational number we place the number under the square root between two consecutive
    11·1 answer
  • Can someone help me with this math problem
    9·2 answers
  • Which of the following is the correct Pythagorean Formula?
    12·1 answer
  • Can the hypotenuse or a leg be a decimal? Why or why not?
    9·1 answer
  • A car travels at an average speed of 80 km/h for 6 hours.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!