What is 269.50 divided by 14?

Can anyone please help me I'm not good at math:)

Rom4ik [11]

Answer:

100 per deposit

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Why do we turn this into a positive number -6 -(3)=

stich3 [128]

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

This is similar to the rule for adding and subtracting: two minus signs become a plus, while a plus and a minus become a minus. In multiplication and division, however, you calculate the result as if there were no minus signs and then look at the signs to determine whether your result is positive or negative. Two quick multiplication examples:

3⋅(−4)=−123⋅(−4)=−12

3 times 4 equals 12. Since there is one positive and one negative number, the product is negative 12.

(−3)⋅(−4)=12(−3)⋅(−4)=12

Now we have two negative numbers, so the result is positive.

Turning to division, you may recall that you can confirm the answer you get by multiplying the quotient by the denominator. If you answer is correct then the product of these two numbers should be the same as the numerator. For example,

123=4123=4

In order to check whether 4 is the correct answer, we multiply 3 (the denominator) by 4 (the quotient):

3⋅4=123⋅4=12

What happens when you divide two negative numbers? For example,

(−12)(−3)=?(−12)(−3)=?

For the denominator (-3) to become the numerator (-12), you would have to multiply it by 4, therefore the quotient is 4.

So, the quotient of a negative and a positive number is negative and, correspondingly, the quotient of a positive and a negative number is also negative. We can conclude that:

When you divide a negative number by a positive number then the quotient is negative.

When you divide a positive number by a negative number then the quotient is also negative.

When you divide two negative numbers then the quotient is positive.

The same rules hold true for multiplication. and the answer is to put a -6 - -3 =3

5 0

3 years ago

If a temp fell from 44to-56what is the change

choli [55]

The change is -100 degrees.

5 0

4 years ago

Need help filling in the blanks: selling price using markup.

Xelga [282]

Answer:

Refer to the explanation.

Step-by-step explanation:

Let's take each one at a time.

1.

To solve for the complement, we simply subtract our markup rate by 100%.

100% - 30% = 70%

Now to solve for the selling price, we use the formula

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{86.74}{0.70}$

Selling Price = $123.91

2.

We do the same process with the first number.

100% - 40% = 60%

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{220.00}{0.60}$

SellingPrice = $366.67

3.

The same as the first two.

100% - 20% = 80%

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{89.50}{0.80}$

SellingPrice = $111.88

4.

Now to solve for the markup rate, we use the formula:

$MarkupRate=\dfrac{Markup}{SelingPrice}$

In this case we first need to find the markup. The markup is the difference between the selling price and the cost.

Selling Price = $235.28

Cost = $199.99

Markup = $235.28 - $199.99

Markup = $35.29

Now the we know our markup, we can then solve for the markup rate using the formula.

$MarkupRate=\dfrac{Markup}{SelingPrice}$

$MarkupRate=\dfrac{35.29}{235.28}$

MarkupRate = 0.1499 x 100 = 14.99% or 15%

5.

Now for the last one, we need to find for the cost. Let's use the selling price formula to find for the cost.

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

Selling Price = $30.77

Complement = 65% or 0.65

This will then give us.

$30.77=\dfrac{Cost}{0.65}$

We multiple both sides of the equation by 0.65 to leave our cost alone.

30.77 x 0.65 = Cost

Cost = $20

4 0

3 years ago

Find the values of A and B PLEASE HELP GIVING BRAINLIEST

erastovalidia [21]

Factoring the roots, the values of A and B are given as follows:

A = 3z.

B = 2.

<h3>What are the values of A and B?</h3>

The expression is:

$\sqrt{\frac{45\alpha z^3}{40y}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}$

We have that:

$\frac{45}{40} = \frac{9}{8}$

Hence:

$\sqrt{\frac{45\alpha z^3}{40y}} = \sqrt{\frac{9\alpha z^3}{8}} = \sqrt{\frac{9\alpha z^2 \times z}{4 \times 2}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}$

Hence, comparing the last two equalities:

A = 3z.

B = 2.

More can be learned about the factoring of roots at brainly.com/question/24380382

#SPJ1

7 0

2 years ago