This is true, because extra detail and collateral information begets you to digress and eventually lead some people astray because they lose interest. You'd rather be straight to the point and give key facts about your model instead.
As a matter of terminology, albino guinea pig actually refers to a white fur guinea pig, whose genotype is homozygous recessive (bb).
If it crossed with a black fur guinea pig and gave 5 black fur offsprings, there is a good chance that the black fur parent is homozygous dominant (BB).
The Punnett square would be as follows:
B B
b Bb Bb
b Bb Bb
So they are all heterozygous black fur offsprings.
However, it is not impossible that the black fur parent be heterozygous, namely
B b
b Bb bb
b Bb bb
Giving a 50% chance on each colour. Thus it is possible (with probability 1/32) that all five offsprings are heterozygous black fur if one of the parents was heterozygous.
In the second case, a homozygous recessive and a homozygous dominant parent will never give a white offspring. So it is sure that the black fur parent is heterozygous, with the following Punnett square:
B b
b Bb bb
b Bb bb
With a 50% probability for each of Bb (black fur) and bb (white fur).
the distribution 4,3 demonstrates this perfectly.
Answer:
A: haploid, each containing 23 chromosomes
Explanation:
Answer:
Single Nucleotide Polymorphisms
Explanation:
Single Nucleotide Polymorphisms (SNPs) occur normally in the DNA (one in 1000) and they have no affect on the phenotype of the person. SNPs pattern is unique in every individual that is why DNA fingerprint is different in every individual.
Sunflowers are dicots because they have seed that have two cotillons, and two seed leaves of food for the embryo. They have really complex leaves with veins all over, not like monocots.
Hope this helped you with your questions.
