Protons and neutrons are in the center of the atom, making up the nucleus. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.
Ocean currents determine the various directions of wind movement.
<h3>What is ocean current?</h3>
Ocean currents are caused by differences in density as well as the temperature of the moving winds across the ocean. In the ocean, warm water is found at the top while cooler water occurs far below.
Warm ocean currents originate near the equator and move towards the poles. The ocean currents control the direction of winds in an area.
Learn more about ocean currents: brainly.com/question/20823678
You can tell the difference by How shiny it is and by how heavy it is
Assuming that the reaction from A and C to AC5 is only
one-step (or an elementary reaction) with a balanced chemical reaction of:
<span>A + 5 C ---> AC5 </span>
Therefore the formation constant can be easily calculated
using the following formula for formation constant:
Kf = product of products concentrations / product of reactants
concentration
<span>Kf = [AC5] / [A] [C]^5 </span>
---> Any coefficient from the balanced chemical
reaction becomes a power in the formula
Substituting the given values into the equation:
Kf = 0.100 M / (0.100 M) (0.0110 M)^5
Kf = 6,209,213,231
or in simpler terms
<span>Kf = 6.21 * 10^9 (ANSWER)</span>
Answer:
0.1082M of Barium Hydroxide
Explanation:
KHP reacts with Ba(OH)2 as follows:
2KHP + Ba(OH)2 → 2H2O + Ba²⁺ + 2K⁺ + 2P²⁻
<em>Where 2 moles of KHP reacts per mole of barium hydroxide</em>
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To solve this question we must find the moles of KHP in 1.37g. With these moles and the reaction we can find the moles of Ba(OH)2 and its molarity using the volume of the solution (31.0mL = 0.0310L) as follows:
<em>Moles KHP -Molar mass: 204.22g/mol-</em>
1.37g * (1mol / 204.22g) = 0.006708 moles KHP
<em>Moles Ba(OH)2:</em>
0.006708 moles KHP * (1mol Ba(OH)2 / 2mol KHP) =
0.003354 moles Ba(OH)2
<em>Molarity:</em>
0.003354 moles Ba(OH)2 / 0.0310L =
<h3>0.1082M of Barium Hydroxide</h3>
