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ch4aika [34]
4 years ago
10

indicators are chemicals that change colour in presence of an acid or an alkali. Universal indicators and pH meters are used to

measure pH. Desccribe how you would use a universal indicator to find the pH of sodium hydroxide. What colour change would you observe
Chemistry
1 answer:
Troyanec [42]4 years ago
7 0

Answer:

Purple. Sodium Hydroxide is an Alkali/base. Bases and Alkalis

have a pH greater than 7, and turn blue-purple in universal

indicator.

Explanation:

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Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.
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PH is the test of acidity or basicity of a solution. it follows the formula: 
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By literature, Ka of HF is 3.5*10^-4 
<span>pKa= -log(Ka)=</span><span> 3.46 </span>

<span>pH = pKa + log [NaF / [HF] </span>

4.05 = 3.46 + log [NaF / [HF] 

log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
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4 years ago
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Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
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Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

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                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

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pOH = -log[OH⁻]

         = -log 0.122

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pH = 14-0.91

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3 years ago
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