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3 years ago

Which of these is an example of a chemical reaction that occurs at a very fast rate?

Chemistry

2 answers:

Aloiza [94]3 years ago

7 0

I believe the answer is an explosion

Sonbull [250]3 years ago

7 0

Answer: Option (c) is the correct answer.

Explanation:

A reaction which is able to occur in fraction of seconds or which is able to occur at an instant rate of time means that reaction is at a very fast rate.

Rusting of iron is not an immediate process as it occurs due to the humidity present within the air an oxide layer develops on the surface of iron. This layer formation does not occur in an instant.

Photosynthesis is a process of formation of food by the plants for themselves in the presence of air, sunlight, carbon dioxide and water.

Rotting wood also takes time and may occur over a period of month or more.

An explosion is an instantaneous process as it occurs within a fraction of seconds.

Thus, we can conclude that out of the given options an explosion is an example of a chemical reaction that occurs at a very fast rate.

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When a 0.245-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.260-g sample

sveticcg [70]

Answer:

The heat of combustion per moles of caffeine is 4220 kJ/mol

Explanation:

Step 1: Data given

⇒ When benzoic acid sample of 0.245 grams is burned the temperature rise is 1.643 °C

⇒ When 0.260 gram of caffeine is burned, the temperature rise is 1.436 °C

⇒ Heat of combustion of benzoic acid = 26.38 kJ/g

Step 2: Calculate the heat released: for combustion of benzoic acid

0.245 g benzoic acid * 26.38 kJ/g = 6.4631 kJ

Step 3: Calculate the heat capacity of the calorimeter:

c = Q/ΔT

Q = 6.4631 kJ / 1.643°C = 3.934 kJ/ °C

Step 4: Calculate moles of a 0.260 g sample of caffeine:

Moles caffeine = Mass caffeine / Molar mass caffeine

0.260 grams/ 194.19 g/mol = 0.0013389 moles

Step 5: Calculate heat released: for combustion of caffeine

Q = c * ΔT

Q = 3.934 kJ/°C * 1.436 °C = 5.65 kJ

Step 6: Calculate the heat of combustion per mole of caffeine

5.65 kJ / 0.0013389 moles = 4219.9 kJ/mol ≈ 4220 kJ/mol

The heat of combustion per moles of caffeine is 4220 kJ/mol

4 0

3 years ago

Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m

nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, W = -80 atm×L ≡ -8,1 kJ

This is the work done in expansion of the gas. As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

4 0

3 years ago

HELP PLZ Calculate the percent composition by mass of iron in Fe(NO3)3

cestrela7 [59]

Hey ik this isn’t a big help but there is a Chem app you can use to get your answers faster rather than waiting for someone to respond. anyways the app is called, ChemCalculator.

5 0

2 years ago

How many molecules are there in 2.3g Of carbon

Alexxandr [17]

Answer: 1.15x10²³ molecules C

Explanation: solution attached:

Convert mass of C to moles using its molar mass then multiply to the Avogadro's number.

8 0

3 years ago

Read 2 more answers

William adds two values , following the rules for using significant figures in computations. He should write the sum of these tw

yuradex [85]

Answer:

when it comes to adding or subtracting numbers, his final answer should have the same number of decimal places as the least precise value.

For example if you add 2 numbers; 10.443 + 3.5 , 10.443 has 3 decimal places and 3.5 has only one decimal place.

Therefore 3.5 is the less precise value.

So when adding these 2 values the final answer should have only one decimal place.

after adding we get 13.943 but it can have upto one decimal place. then the second decimal place is less than 5 so the answer should be rounded off to 13.9.

the answer is the same number of decimal places as the least precise value

Explanation:

I think this is the answer I'm not sure

7 0

2 years ago