<span>Mass Number = (Atomic Number) + (Number of Neutrons) so you solve for the Number of Neutrons and you get:
Number of Neutrons = (Mass number) - (Atomic Number)
Mass Number equals protons plus neutrons, round atomic weight to nearest whole number
Atomic Number equals number of Protons</span>
Answer : The maximum amount of nickel(II) cyanide is 
Explanation :
The solubility equilibrium reaction will be:
Initial conc. 0.220 0
At eqm. (0.220+s) 2s
The expression for solubility constant for this reaction will be,
![K_{sp}=[Ni^{2+}][CN^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BNi%5E%7B2%2B%7D%5D%5BCN%5E-%5D%5E2)
Now put all the given values in this expression, we get:
Therefore, the maximum amount of nickel(II) cyanide is
Answer:
The work is -6,497.54 J
Explanation:
Work is the amount of energy transferred from one system to another by a force when a displacement occurs.
The work exchanged for a gas depends on the transformation it performs to go from the initial state to the final state.
The pressure - volume work done by a system that compresses or expands at constant pressure is given by the expression:
W= -P*ΔV
where
- W is the work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J), which is equivalent to Pa*m³
- P: Pressure. Its unit of measurement in the International System is the pascal (Pa).
- ∆V: Volume variation (∆V = Vfinal - Vinitial). Its unit of measurement in the International System is cubic meter (m³)
In this case:
- Wsystem=?
- P= 5.63 atm=570,459.8 Pa (being 1 atm=101325 Pa)
- ΔV=Vfinal - Vinitial= 15.61 L - 4.22 L= 11.39 L= 0.01139 m³ (being 1 L=0.001 m³)
Replacing:
W= -570,459.8 Pa*0.01139 m³
Solving:
W=-6,497.54 J
<u><em>The work is -6,497.54 J</em></u>
