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1 year ago

If g(x)= x+1/x-2 and h(x)=4-x, what is the value of (g times h)(-3)

1 answer:

6 0

$g(-3)=\frac{-3+1}{-3-2}=\frac{2}{5} \\ \\ h(-3)=4-(-3)=7 \\ \\ (g\times h)(-3)=7\left(\frac{2}{5} \right)=\boxed{\frac{14}{5}}$

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Write each complex number in rectangular form. a. 2(cos(135)+i sin(135)) b. 3(cos(120))+i sin(120)) c. 5(cos(5pi/4)+i sin(5pi/4)

bagirrra123 [75]

$\bf r\left[ cos\left( \theta \right)+i\ sin\left( \theta \right) \right]\quad 
\begin{cases}
x=rcos(\theta )\\
y=rsin(\theta )
\end{cases}\implies 
\begin{array}{llll}
x&,&y\\
a&&b
\end{array}\implies a+bi\\\\
-------------------------------\\\\
2\left[ cos\left( 135^o\right)+i\ sin\left( 135^o\right) \right]\impliedby r=2\qquad \theta =135^o
\\\\\\
2\left( -\frac{\sqrt{2}}{2} \right)+i\ 2\left( \frac{\sqrt{2}}{2}\right)\implies -\sqrt{2}+\sqrt{2}\ i$

$\bf -------------------------------\\\\
3\left[ cos\left( 120^o\right)+i\ sin\left( 120^o\right) \right]\impliedby r=3\qquad \theta =120^o
\\\\\\
3\left( -\frac{1}{2} \right)+i\ 3\left( \frac{\sqrt{3}}{2}\right)\implies -\frac{3}{2}+\frac{3\sqrt{3}}{2}\ i$

$\bf \\\\
-------------------------------\\\\
5\left[ cos\left( \frac{5\pi }{4}\right)+i\ sin\left( \frac{5\pi }{4}\right) \right]\impliedby r=5\qquad \theta =\frac{5\pi }{4}
\\\\\\
5\left( -\frac{\sqrt{2}}{2} \right)+i\ 5\left( -\frac{\sqrt{2}}{2}\right)\implies -\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}\ i$

$\bf -------------------------------\\\\
4\left[ cos\left( \frac{5\pi }{3}\right)+i\ sin\left( \frac{5\pi }{3}\right) \right]\impliedby r=4\qquad \theta =\frac{5\pi }{3}
\\\\\\
4\left( \frac{1}{2} \right)+i\ 4\left( -\frac{\sqrt{3}}{2}\right)\implies \frac{1}{2}-\frac{\sqrt{3}}{2}\ i$

3 0

3 years ago

Can someone solve this for me with their explanation please?

Lana71 [14]

First you want to subtract 36

so it looks like this $\sqrt[4] {(4x+164)^3}=64$

Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)

${(4x+164)^3}=64^4$ which is equal to ${(4x+164)^3}=16777216$

Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]

Then you end up with the equation 4x+164=256

Then subtract 164 to both sides

4x=92

then divide 92 by 4

Then you get x=23

7 0

3 years ago

Write a division problem whose quotient has its first digit in the hundreds place

Margaret [11]

Quotient is another name for the answer to a division problem

the hundreds place is the 3rd number before the decimal, 9999999.0
^this one

so you need to find a division problem that equals something between 100 and 999

1000 divided by 10 is a good one, the answer to that problem is 100, and 100 has its first digit in the hundreds place.

8 0

2 years ago

-7(-7-9)-7v<br> what is the answer

liraira [26]

Answer:

112-7v

Step-by-step explanation:

4 0

3 years ago

8 customers entered a store over the course of 16 minutes. At what rate were the customers entering the store in minutes per cus

lilavasa [31]

Answer:

<h3>2min/customer</h3>

Step-by-step explanation:

If 8 customers entered a store over the course of 16 minutes, then;

8 customers = 16 minutes.

The rate at which the customers are entering is expressed as;

Rate = Time (in minutes)/amount of customers;

Given

Time = 16 minutes

Amount of customers = 8 customers

Rate = 16min/8customers

Rate = 2min/customer

Hence the rate at which the customers entering the store in minutes per customer is 2min/customer.

4 0

2 years ago