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HACTEHA [7]
3 years ago
10

Draw two triangles has length 6 and width 9.The second has length 3x and width 9.Write at least three different expressions for

the sum of the areas of the rectangles.

Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0

Step-by-step explanation:

Three different expressions for the sum of the areas of the rectangles.

-The first is:

AREA = BASE X HEIGHT

2.A second way is:

AREA= Constant x (Variable + Constant)

<em><u>ADDITIONAL INFORMATION: </u></em>

A file with the drawing of the two triangles with their lengths and widths is attached.

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A car travels for 4(t+3) hours at a constant speed of 10(t+3) km/h. If the total distance travelled by the car is 810 km, find t
IceJOKER [234]

Step-by-step explanation:

\because \: time \times speed  = distance \\  \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \:  \{2(t + 3) \}^{2} =  {9}^{2}  \\  \therefore \:  \{2(t + 3) \} =  {9}   \\  \therefore \: t + 3 =  \frac{9}{2}  \\ \therefore \: t  =  \frac{9}{2}  - 3 \\  \therefore \: t  =  \frac{9 - 6}{2}  \\  \therefore \: t  =  \frac{3}{2}  \\ \therefore \: t  =  1.5 \: hrs  \\

\because \: time \times speed  = distance \\  \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \:  \{2(t + 3) \}^{2} =  {9}^{2}  \\  \therefore \:  \{2(t + 3) \} =  {9}   \\  \therefore \: t + 3 =  \frac{9}{2}  \\ \therefore \: t  =  \frac{9}{2}  - 3 \\  \therefore \: t  =  \frac{9 - 6}{2}  \\  \therefore \: t  =  \frac{3}{2}  \\ \therefore \: t  =  1.5 \: hrs  \\ speed \: of \: car = 10(t + 3) \\ \hspace{60 pt} = 10(1.5 + 3) \\   \hspace{60 pt}= 10 \times 4.5 \\ \red{ \boxed{ \bold{ \therefore \: speed \: of \: car  = 45 \:km/ h}}} \\

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3 years ago
Factor the algebraic expression.<br> 240q- 760u + 104i- 52b - 36i
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4 - 2x = 10 plz solve
posledela

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x=7

Step-by-step explanation:

Opposite of subtraction is adding so you do 4+10=14 so that means that x equals seven because 2x7 equals 14.

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Read 2 more answers
HELP NEEDED!!! WILL MARK BRAINLIEST!!!
erma4kov [3.2K]

Answer:

x(x + 1)

Step-by-step explanation:

\frac{2x + 1}{ \frac{1}{x} +  \frac{1}{x + 1}  }

Make denominators same:

\frac{2x + 1}{ \frac{x + 1}{x(x + 1)} +  \frac{x}{(x + 1)}  }

Add the numerators:

\frac{2x + 1}{ \frac{x + 1 + x}{x(x + 1)} }

\frac{2x + 1}{\frac{2x + 1}{x(x + 1)} }

Apply the rule:

\frac{a}{ \frac{b}{c} }  =  \frac{a \times c}{b}

Therefore,

\frac{(2x + 1)\times x(x + 1))}{2x + 1}

Cancel out common factor of 2x+1:

x(x + 1)

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