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kenny6666 [7]
2 years ago
9

Drag each label to the correct location on the image. Each label can be used more than once, but not all labels will be used.

Mathematics
1 answer:
pickupchik [31]2 years ago
8 0

(1) When Emma is standing at the top of the mountain, the energy encountered is potential energy.

(2) When Emma is jumping down from the mountain top, the energy encountered is both kinetic energy and potential energy.

(3) The energy creating the tensional force on the rope at Emma’s lowest position is elastic potential energy.

(4) When Emmas is bouncing back, he will encounter both kinetic energy and potential energy.

<h3>Conservation of energy</h3>

The energy encountered by Emma and the rope at each point is determined from the principle of conservation of mechanical energy.

<h3>1.0 Emma standing on top of mountain </h3>

When Emma is standing at the top of the mountain, the energy encountered is potential energy this is due to his position above the ground level.

P.E  = mgh

<h3>2.0 Emma jumping down from mountain top</h3>

When Emma is jumping down from the mountain top, the energy encountered is both kinetic energy and potential energy. This is as a result of his position above the ground level and his motion downwards.

M.A = K.E + P.E

<h3>3.0 Tension in rope at Emma’s lowest position</h3>

The energy creating the tensional force on the rope at Emma’s lowest position is elastic potential energy.

U = ¹/₂kx²

<h3> 4.0 Emma bouncing back</h3>

When Emmas is bouncing back, he will encounter both kinetic energy and potential energy due to his motion and position above the ground.

Learn more about potential energy here: brainly.com/question/14427111

#SPJ1

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alternate angles are on opposite sides of the transversal, and each attached to a different (parallel) line.

If they are both enclosed by the parallel lines, they are alternate interior angles (examples: angles 2 and 3, 6 and 7)

If they are both outside of the two parallel lines, they are alternate exterior angles (examples: angles 1 and 4, 5 and 8)

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Answer:

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Step-by-step explanation:

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Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

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P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

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The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

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