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Pavlova-9 [17]
2 years ago
12

Which row of the input/output table is incorrect? y = 2 x - 3 x y Row A 3 3 Row B 5 7 Row C 7 11 Row D 10 15 Row B Row C Row A R

ow D
Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
4 0

The row of the input/output is incorrect is Row D.

<h3>What is equation?</h3>

Given equation: y = 2x - 3

For, row A:  

x = 3

y = 2x - 3

So,

y = 2(3) - 3

y = 3, which is correct

For row B:

x = 5

y = 2x - 3

So,

y = 2(5) - 3

y = 7, which is also correct.

For row C:

x = 7

y = 2x - 3

So,

y = 2(7) - 3

y = 11, which is also correct.

For, row D:

x = 10

y = 2x - 3

So, y = 2(10) - 3

y  = 17, which is incorrect.

Hence, the row of the input/output is incorrect is Row D.

Learn about this concept here:

brainly.com/question/12879527

#SPJ1

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Answer:

S=4.5

Step-by-step explanation:

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3 years ago
How do you solve and simplify
DedPeter [7]
F(x) = 1/(x+2)   & g(x) = x/(x-3)


(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:

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3 years ago
PROBLEM #5
andrezito [222]

Answer:

12.5%

Step-by-step explanation:

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10 / 80 = 0.125

Convert decimal to percent.

0.125 = 12.5%

5 0
3 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
A survey was taken of a random sampling of residents of New York City and Los Angeles to compare how many of them own a car. A 4
erma4kov [3.2K]

Answer:

The correct option is;

There is a greater percentage of LA residents who own a car than NYC residents who do

Step-by-step explanation:

The values are presented as follows;

LA residents who own a car = 3251

NYC residents who own a car = 1478

Total residents who own a car = 4729

LA residents who do not own a car = 869

NYC residents who do not own a car = 6182

Total residents who do not own a car = 7051

Total LA residents sampled = 4120

Total NYC residents sampled = 7660

Total residents of both cities sampled = 11780

Percentage of LA residents who own a car = (3251/4120)×100 = 78.9%

Percentage of NYC residents who own a car = (1478/7660)×100 = 19.3%

The total number of people in the poll who own a car = 4729

Therefore, the correct option is that there is a greater percentage of LA residents who own a car than NYC residents who do.

7 0
3 years ago
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