Answer:
chlorine Will be at highest
The group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from <u>Alkenes</u>
<h3>What are organic compounds?</h3>
Organic compounds are compounds which contains carbon and hydrogen
Some few classes or organic compounds or hydrocarbons are as follows:
- Alkanes
- Alkenes
- Alkynes
- Alkanols
- Alkanoic acid
- Ketones
- Esters
So therefore, the group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from <u>Alkenes</u>
Learn more about organic compounds:
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<u>Answer:</u> The standard enthalpy of formation of is -92.7 kJ/mol
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the standard enthalpy of formation of is -92.7 kJ/mol
Answer:
0.625 moles of CO2
Explanation:
Remark
The equation used (I take it) is a hydrocarbon burning. If it is not, leave a note on the question. The method I will use is
- Find the moles CH4
- Use the equation to adjust the number of moles of the product. It the balance numbers are the same, move on.
Equation
CH4 + 2O2 ====> CO2 + 2H2O
Givens
10 grams CH4
Solution
Number of moles of CH4
mol CH4 = given mass / molar mass.
given mass = 10 grams
molar mass CH4
- C = 12
- H = 4 * 1 <u> 4</u>
- molar mass 16
Moles of CH4
mol = given mass / molar mass
mol = 10 grams / 16 grams
mol = 0.625
Answer
Since the number of moles of CO2 and CH4 are the <u><em>same </em></u>in the balanced equation. the answer is 0.625 mols of both.