Please answer

Dana wants to determine the molar mass of magnesium hydroxide, Mg(OH)2. Which calculation should she use?

aleksandr82 [10.1K]

Answer C. is correct:

(molar mass of Mg) + (2 x molar mass of O) + (2 x molar mass of H)

:-) ;-)

3 0

3 years ago

Read 2 more answers

What are homologous series

Semenov [28]

Answer :

A homologous series is a family of hydrocarbons with similar chemical properties who share the same general formula. We will look at three hydrocarbon series: alkanes, alkenes and the cycloalkanes. Hydrocarbons are compounds that contain only hydrogen and carbon.

3 0

3 years ago

In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

Answer:

For A: The standard cell potential of the reaction is 4.4 V

For B: The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C: The reaction is spontaneous as written.

Explanation:

For A:

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

Oxidation half reaction: $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

Reduction half reaction: $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

For B:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C:

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0

4 years ago

How many orbitals surround the nucleus in a neutral atom of sulfur (S)? A. 1 B. 3 C. 9 D. 6

Igoryamba

Answer:

it may be 3

Explanation:

i hope that..

5 0

3 years ago

Identify each activity as an observation, a hypothesis, an experiment, or a conclusion

tekilochka [14]

Answer:

A- observation

B- hypothesis

C,D,E- experiment

F- conclusion

Explanation:

Lucia has just carried out the scientific process. An observation refers to paying close attention to a particular phenomenon in nature. This leads to the proposition of an intelligent guess about the observed phenomenon. This intelligent guess is called a hypothesis.

The hypothesis now guides the design of an experiment designed to confirm or disprove the hypothesis. The results of the experiment now leads to the formulation of a conclusion as Lucia has just done.

4 0

3 years ago