To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:
r1/r2 = √(m2/m1)
where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol)
r1 = 1.6r2
1.6 = √(44.01 / m1)
m1 = 17.19 g/mol
0.02 mol NaCl
Explanation:
(0.2M NaCl)×(0.10 L) = 0.02 mol NaCl
Let the 8% solution be A, the 20% solution be B and the final solution be C.
C = A + B
C = 12 + B
0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters
C = 12 + 24
C = 36 Liters
Given:
Number of items = 25
Price per item = $18
<u>To determine:</u>
The total revenue
<u>Explanation:</u>
Total revenue = quantity * price per item
= 25 items * 18 dollar/ 1 item = $450
Ans: A) The total revenue is $450
