Answer:
Part 1) AJ drawn the parabola opening upwards, instead of drawing it opening downwards
Part 2) see the explanation
Step-by-step explanation:
Part 1) What mistake did AJ make in the graph?
we have
This is the equation of a vertical parabola written in vertex form
The parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The vertex is the point (-2,-1)
therefore
AJ drawn the parabola opening upwards, instead of drawing it opening downwards
Part 2) Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?
take the values x=-4 and x=4
For x=-4
substitute the value of x in the quadratic equation
For x=4
substitute the value of x in the quadratic equation
According to AJ's graph for the value of x=-4 the function should be positive, however it is negative and for the value of x=4 the function should be positive and the function is negative
therefore
AJ made a mistake in the graph
Answer:
x=-6
Step-by-step explanation:
2x+y=-4
5x+3y=-6
solve :
multiply first equation by 3
6x+3y=-12
5x+3y=-6
subtract the two equations : 6x+3y-5x-3y=-12-(-6)
x=-12+6
x=-6
Answer:
3
Step-by-step explanation:
3 is closer to 0
In geometry,
A point represents a point
Two points define a line extended on both sides of the points.
Two points define a ray if it extends on only one side of either of the points.
Three or more than three points define a plane.
Now as far as a wall is considered, it is a flat surface on which we can plot infinite points.
Hence the wall represents a plane.
Option C) is the right answer.