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hammer [34]
3 years ago
10

A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. T

he term paper counts as 20% of the course grade. The final examination counts as 20% of the course grade. Alan has test scores of
92, 78, 82, and 90.
Alan received an 80 on his term paper. His final examination score was 86. Use the weighted mean formula to find Alan's average for the course. (Round your answer to one decimal place.)

Mathematics
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

The Alans's average for the course is 84.5

Step-by-step explanation:

We are given

There are 4 tests, A Term paper and a Final examination.

Score = 92, 78, 82, 90.

Term paper score = 80

Final examination score = 86

Weighted mean = ∑ w.f/∑w

     also the sum of all the weights is 100% = 1

weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1

                         = 51.3 + 33.2

                         =  84.5

Therefore the Alans's average for the course is 84.5

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Answer:

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Explanation:

Mutually exclusive events are events that cannot occur at the same time.  Our spinner has two grey sections, on 1 and 3; and two white sections, on 2 and 4.

This means that the spinner cannot land on a shaded (grey) portion and land on an even number at the same time, since the grey sections are numbered 2 and 4, both of which are even numbers.

The spinner also cannot land on a shaded (grey) portion and land on a number greater than 3 at the same time; this is because the only number greater than 3 on the spinner is 4, which is a white portion.

The spinner cannot land on an unshaded (white) portion and land on an odd number, since the white sections are labeled 2 and 4, which are both even.

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Firewood is stacked in a pile. The bottom row has 20 logs, and the top row was 14 logs. Each row has one more log than the row a
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Since, each row has one more log than the row above it

so, this is arithematic sequence

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=14

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