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ryzh [129]
4 years ago
7

NEED HELP NOW 100 POINTS!!!!

Mathematics
2 answers:
Maru [420]4 years ago
7 0
So we need to find the inequality, Simple! 
So we only have 5 dollars. That we cannot change. 
But the snadwich, however, we can change how much we buy. But this problem is asking us how many we can buy. So that is an x. So far, we have 2.25x.
Then we have to use the inequality sign 'less than or equal to' because we can buy less or equal to 5 dollars. 

So the equation is 2.25x \leq 5.
Then we solve by isolating the x. We divide 2.25 both sides then we get x \leq 2.
yarga [219]4 years ago
6 0

Answer:

5.

2.25x\leq 5\\x\leq 2

Step-by-step explanation:

You might be interested in
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
I need help fast. please help me​
galina1969 [7]

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EXPLANATION :

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7 0
4 years ago
Read 2 more answers
What should be the paper weight
nata0808 [166]

Answer:

6.25 cm

Step-by-step explanation:

\rho=\dfrac{m}{V} \\\\V_{\text{pyramid}}= A_{\text{base}}\cdot h \cdot \dfrac{1}{3} \\\\1.6=\dfrac{400}{V} \\\\V=120 \cdot h \cdot \dfrac{1}{3} \\\\1.6=\dfrac{400}{40h} \\\\1.6=\dfrac{10}{h} \\\\1.6h=10 \\\\h=\dfrac{10}{1.6}=6.25\text{ cm}

Hope this helps!

8 0
4 years ago
Read 2 more answers
The function f(x) is an increasing function about which little else is known about other than f(2)=7 and f'(2)=5. Find (f^-1)'(7
andreyandreev [35.5K]

Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have

f^(-1)(f(x)) = x

Differentiating with the chain rule gives

(f^(-1))'(f(x)) f'(x) = 1

so that

(f^(-1))'(f(x)) = 1/f'(x)

Let x = a; then

(f^(-1))'(f(a)) = 1/f'(a)

(f^(-1))'(b) = 1/f'(a)

In particular, we take a = 2 and b = 7; then

(f^(-1))'(7) = 1/f'(2) = 1/5

3 0
3 years ago
50 POINTS!!! PLEASE HELP QUICK! In the figure below, AB is a diameter of circle P.
Minchanka [31]

Answer:

43°

Step-by-step explanation:

7x+1+9x-7=90

16x-6=90

16x=96

x=6

the minor arc AD = 7x+1 =7(6)+1

= 42+1=43°

6 0
3 years ago
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