Question

Mr. Mole left his burrow and started digging his way down at a constant rate.

Answer 1

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute $= \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},$

$\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.$

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow $= -18 - 5(-2.4) = -18+12 = -6.$

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

Answer 2

Answer:

2.4

Step-by-step explanation: