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2 years ago

A table of data is given.

Mathematics

1 answer:

Oliga [24]2 years ago

6 0

Answer:

The choice D.

$f(x) = 3 {(0.2)}^{x}$

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If the expression 3x+10 is equal to 6 for some value of x, then what is the value of 3x+2 equal to for the same value of x ?

Murrr4er [49]

Answer:

149

Step-by-step explanation:

If the expression 3x+10 is equal to 6 for some value of x, then what is the value of 3x+2 equal to for the same value of x ?

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3 years ago

Question 5

kramer

Answer:

The possible numbers that Kelley might have scored are:

1, 2, 3, 4, 5, 6, 7 and 8

Step-by-step explanation:

Please kindly see the attached file for more explanation

8 0

3 years ago

Given h(t)=-2(t+5)^2+4, find h(-8)

alexandr402 [8]

Substitute -8 for t in <span>h(t)=-2(t+5)^2+4:

h(-8) = -2(-8+5)^2 + 4 = -2(-3)^2 + 4 = -2(9) + 4 = -18 + 4

h(-8) = -18 + 4 = -14 (answer)</span>

5 0

3 years ago

Read 2 more answers

Two hot air balloons are traveling along the same path away from a town, beginning from different locations at the same time. He

kolbaska11 [484]

9514 1404 393

Answer:

D. Henry's started farther, went faster

Step-by-step explanation:

Henry's balloon traveled 18 additional miles (from 30 to 48) in 2 hours, so had a speed of 18mi/(2h) = 9 mi/h. The equation for his position could be ...

y = 9x +30 . . . . . 9 is the rate of change; 30 is the initial value

Comparing this to Tasha's position function, we see her balloon started 20 miles from town and traveled 8 miles per hour.

Henry started farther from town and traveled faster.

5 0

2 years ago

A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of the triangle? Round your answer to the

larisa86 [58]

Use the distance formula to find the length of the sides, then add them up to find the perimeter.

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points in the form of (x1, y1), (x2, y2).

(-1, 2), (3, 1)

$\sf d=\sqrt{(3+1)^2+(1-2)^2}$

$\sf d=\sqrt{(4)^2+(-1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(3, 1), (7, 2)

$\sf d=\sqrt{(7-3)^2+(2-1)^2}$

$\sf d=\sqrt{(4)^2+(1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(7, 2), (-1, 2)

$\sf d=\sqrt{(-1-7)^2+(2-2)^2}$

$\sf d=\sqrt{(-8)^2+(0)^2}$

$\sf d=\sqrt{64+0}$

$\sf d=\sqrt{64}=8$

So the perimeter will be:

$\sf 8+\sqrt{17}+\sqrt{17}\approx\boxed{\sf 16.25}$

3 0

3 years ago