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rusak2 [61]
3 years ago
12

Rosario is rollling a six- sided cube. Rosario rolls the number cube twice. What is the probability that Rosario gets the number

1 twice in a row?
A. 1/36
B.1/6
C. 1/3
D.1
Part two: tony flips a coin and gets heads. Ge tells his friend his friend that he can get heads two more times in a row. What is the probability that tony will flip a coin and gets heads three more times in a row?
A.1/8
B.1/2
C.1 & 1/2
D. 2
Whats the answer for each part?
First answer that explains gets to me marked branilest& extra points. I need help ASAP.
Thanks
Mathematics
1 answer:
icang [17]3 years ago
5 0
Part 1:the answer is 1/36
each time we roll the dice, the whole probabilities are 6
if we roll it two times
6*6=36

part 2

it's 1/8

each time we flip a coin, the whole probabilities are 2

if we flip it 3 times

2*2*2=8




good luck
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890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(AB)(BC)

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

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169 = 25 + BC²

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Area of the triangular base = \frac{1}{2}(5)(12)

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Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

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Volume of one spherical bead = \frac{4}{3}\pi r^{3}

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Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

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