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Murrr4er [49]
2 years ago
10

Select the fraction that is equivalent to one third.

Mathematics
1 answer:
denpristay [2]2 years ago
5 0

Answer:

\frac{2}{6} (two sixths)

Step-by-step explanation:

if we scale the fraction 1 / 3 to find equivalent fractions, we can simply multiply both numbers by the same factor.

So, by multiplying both 1 and 3 by two, we will have an equivalent fraction

1      ×  2        =      2
_                            _

3      ×  2        =      6

This means that

\frac{1}{3} (one third) is equivalent to \frac{2}{6} (two sixths)

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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
The mean of x y and z is 20. find the mean of x-5 y+4 z-5
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Answer:

18

Step-by-step explanation:

Sum of x, y and z = 20 × 3

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x-5+y+4+z-5 = 60-5+4-5

                    = 54

Mean of x-5, y+4 and z-5

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Answer:

x = ± 2i

Step-by-step explanation:

The equation has no real roots, gut has complex roots

Given

x² = - 4 ( take the square root of both sides )

x = ± \sqrt{-4}

  = ± \sqrt{4(-1)}

[ Note that \sqrt{-1} = i ]

  = ± \sqrt{4} × \sqrt{-1} = ± 2i

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The graph plots four equations, A, B, C, and D: Line A joins ordered pair negative 6, 16 and 9, negative 4. Line B joins ordered
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The pair of equations that has (0, 8) as its solution is: A. equation A and equation C.

<h3>What is the Solution to a System of equations?</h3>

The solution to a system of linear equations that are graphed is the pair of x and y coordinates of the points where two lines intersect.

In the graph given, the lines representing equations A and C intersect at point (0, 8). Therefore, the pair of equation that has a solution of (0, 8) is: A. equation A and equation C.

Learn more about solution of a system of equations on:

brainly.com/question/847634

#SPJ1

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